Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Textbook Question
Chapter 20, Problem 45P
Compound W
Figure 20.6 The
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A compound A of mass 114 has the following elemental analysis: C = 63.14%, H=8.83%.
The IR, 1H NMR and 13C NMR spectra are given below.
1) Assign and interpret all the data from the 1H NMR and 13C NMR spectra. Propose a formula
for A.
7.0
175
с
3000
1,3; 13
I=1
6.0
150
I=1
с
5.0
CH₂
125
2000
Explain why the answer is this one :
CH,—CH,—0
4,2; 60
mavermy
I=2
cm-1
4.0
100
1500
3.0
75
135
167 |
CH₂
6
125
CH 3
1,95 ; 18
I=3
1000
2.0
50
H
5,5
I=3
1.0
CH₂
CH₂
25
500
Ppm
ppm
Indicate two basic differences that exist between the spectra of 1H y 13C in NMR.
An unknown compound has the formula C4H12O. Elucidate its structure by scrutinizing its 1H NMR spectra, shown. Specifically, label each different type of H atom in the final structure with its NMR chemical shift in ppm.
Chapter 20 Solutions
Organic Chemistry
Ch. 20 - Prob. 1PPCh. 20 - Prob. 2PPCh. 20 - Practice Problem 20.3
Write a mechanism that...Ch. 20 - Prob. 4PPCh. 20 - PRACTICE PROBLEM 20.5 Outline a preparation of...Ch. 20 - Prob. 6PPCh. 20 - Prob. 7PPCh. 20 - Prob. 8PPCh. 20 - Prob. 9PPCh. 20 - Prob. 10PP
Ch. 20 - Practice Problem 20.11 In the preceding examples...Ch. 20 - Prob. 12PPCh. 20 - Prob. 13PPCh. 20 - Practice Problem 20.14
Outline a synthesis of...Ch. 20 - Prob. 15PPCh. 20 - Prob. 16PPCh. 20 - Prob. 17PPCh. 20 - Prob. 18PPCh. 20 - Prob. 19PCh. 20 - 20.20 Give common or systematic names for each of...Ch. 20 - Which is the most basic nitrogen in each compound?...Ch. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Show how you might synthesize each of the...Ch. 20 - Prob. 25PCh. 20 - 20.26 Provide the major organic product from each...Ch. 20 - Prob. 27PCh. 20 - 20.28 What products would you expect to be formed...Ch. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Write equations for simple chemical rests or state...Ch. 20 - Prob. 33PCh. 20 - Explain the following, including mention of key...Ch. 20 - 20.35 Provide a detailed mechanism for each of the...Ch. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - 20.40 Give structures for compounds R-W:
Ch. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Diethylpropion (shown here) is a compound used in...Ch. 20 - Prob. 44PCh. 20 - 20.45 Compound W is soluble in dilute aqueous HCI...Ch. 20 - 20.46 Propose structures for compounds X, Y, and...Ch. 20 - Compound A(C10H15N) is soluble in dilute HCI. The...Ch. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - For each of the following, identify the product...Ch. 20 - 20.51 Develop a synthesis for the following...Ch. 20 - 20.52 When phenyl isochiocyanatc, , is reduced...Ch. 20 - Prob. 53PCh. 20 - 20.54 Propose a mechanism that can explain the...Ch. 20 - When acetone is treated with anhydrous ammonia in...Ch. 20 - Prob. 56P
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- A hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forwardTreatment of compound C (molecular formula C9H12O) with PCC affords D (molecular formula C9H10O). Use the 1H NMR and IR spectra of D to determine the structures of both C and D.arrow_forwardThe NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 . The 1H and 13C peaks are also listedbelow. Provide a full analysis of the NMR spectra for compound 1. correct assignment of NMR spectra of both 13C spectra. correct rationalisation of 13C spectrum1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).13C NMR (101 MHz, CDCl3) δ 160.79, 154.09, 143.43, 131.85, 127.87, 124.44, 118.86,116.94, 116.74.Note: There are two carbon peaks in the 13C spectrum that are so close together that they are not differentiable at the resolution in this experiment. you should be able to assign these peaks to one of two carbon atoms in 1.arrow_forward
- 08) The NMR spectra of the two isomeric compounds with formula C3H5ClO2 are shown in letters a and b. Low-field protons appearing in the NMR spectrum around 12.1 and 11.5 ppm, respectively, are shown highlighted. Draw the structures of the isomers.arrow_forwardName the following compounds A and B. How could you distinguish these two molecules by using 1H NMR and IR techniques? Propose an analytical technique to determine the iron content of these compounds. Calculate the mass percentages of C and H of compound B (C: 12.01 g/mol; H: 1.008 g/mol; Fe: 55.845 g/mol).arrow_forwardLl.128.arrow_forward
- Identify the structures of isomers H and I (molecular formula C8H11N).a.Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm−1b.Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm−1arrow_forwardThe HNMR , CNMR , 2D NMR SPECTRA OF COMPOUND M1 ARE ATTACHED. WHAT IS STRUCTURE OF IT ? IS IT SYMMETRICAL REGARDS TO ITS CNMR SPECTRUM ? WHAT IS THE STRUCTURE SUGGESTION AND WHY ?arrow_forwardCompound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forward
- A molecule of the molecular formula C5H11Br gives rise to the NMR spectrum below. When reacted with NaOH and water, it forms a product which by NMR has 2 protons 1H at 5.4 ppm and 1H at 5.5 ppm each having a 3J coupling of 17 Hz. (other protons also present) The product also has an IR stretch at 1550 cm 1. Provide the structures of the starting material and product. NaOH H,0 C;H„Br 6H triplet 4H quintet 1H quintet 10 8 Ppmarrow_forwardAnalysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm–1. Figure below shows the NMR spectrum of the compound. Which of the following is this compound? A. 3-hydroxybutanalB. Methyl propionateC. Ethyl acetateD. 2-methylpropanoic acidE. Methoxyacetonearrow_forwardAn organic compound B with formula C6H14O has the following: IR Spectroscopy 2974 cm-1, 1080 cm-1 Mass Spectrometry 102 (M+), 87, 73 1H NMR Spectroscopy Eight signals at δ 1.10 (d, 3H), 1.13 (dd, 3H), 1.14 (dd, 3H), 1.59 (ddq, 1H), 1.60 (ddq, 1H), 3.19 (ddq, 1H), 3.51 (dq, 1H), 3.50 (dq, 1H). Compound B is obtained by the reaction of compound A with NaH followed by CH3CH2Br. The stereochemistry of A is "S" Using this information, deduce a plausible structure for Compound A with correct stereochemistry.arrow_forward
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