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Compound
FIGURE 20.8 The broadband proton-decoupled
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Organic Chemistry
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- Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoningarrow_forward19. A compound with molecular formula C6H12O2 exhibits two singlets in its 1H NMR spectrum, at d 1.4 (9H) and d 2.0 (3H). Its IR spectrum shows a strong absorption band near 1740 cm-1. What is the structure for this compound? Show the correlation of the spectra with the molecular structure.arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forward
- Draw the structure of the compound that produced the spectra below. The infrared spectrum has strong bands at 1720 and 1738 cm-1.arrow_forwardA hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forwardCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)arrow_forward
- A compound of formula C11H16N2 gives the IR, 1H NMR, and 13C NMR spectra shown. The proton NMR peak at δ 2 disappears on shaking with D2 Propose a structure for this compound, and show how your structure accounts for the observed absorptions.arrow_forwardAn organic compound B with formula C6H14O has the following: IR Spectroscopy 2974 cm-1, 1080 cm-1 Mass Spectrometry 102 (M+), 87, 73 1H NMR Spectroscopy Eight signals at δ 1.10 (d, 3H), 1.13 (dd, 3H), 1.14 (dd, 3H), 1.59 (ddq, 1H), 1.60 (ddq, 1H), 3.19 (ddq, 1H), 3.51 (dq, 1H), 3.50 (dq, 1H). Compound B is obtained by the reaction of compound A with NaH followed by CH3CH2Br. The stereochemistry of A is "S" Using this information, deduce a plausible structure for Compound A with correct stereochemistry.arrow_forwardPropose a structure for D (molecular formula C9H9ClO2) consistent with the given spectroscopic data. 13C NMR signals at 30, 36, 128, 130, 133, 139, and 179 ppmarrow_forward
- Draw the structure of a compound with the formula C5H10O2 (along with the reasons of choosing it) which, upon analysis, gave key peaks in an infrared spectrum at 3450 cm-1 and 1713 cm-1, as well as the following 1H-NMR spectrum.arrow_forward2 (a) Compound A has the molecular formula of CsH100. The IR and 'H NMR spectra are given as follows. Deduce the structure of A. 3H 3H 2H wllen 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 14 1.0 0.8 0.8 PPMarrow_forwardPropose a structure for compound X (molecular formula C6H12O2), which gives a strong peak in its IR spectrum at 1740 cm−1. The 1H NMR spectrum of X shows only two singlets, including one at 3.5 ppm. The 13C NMR spectrum is given below. Propose a structure for X.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning