1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +
1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +
Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter19: Enolate Anions And Enamines
Section19.9: Crossed Enolate Reactions Using Lda
Problem JQ
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Transcribed Image Text:1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in
the following reaction.
Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is
a weak base used to neutralize strong acid (pKa < 0) produced by the reaction.
Redraw the product to show the configuration(s) that form at C-2 and C-4.
Br2
OH
CH2Cl2
Na* HCO3
Br
HO
OH
+ Na Br +
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