log [S208^2-] (mol/L) Log In] mol/L a. Assuming the rate expression for this system is in the form, rate - k[I]*[S₂O,²], it should be possible to determine the values of x and y from the data obtained. Show why a plot of log(time) vs log[I] for runs 1-4 will give a slope of -x and log(time) vs. log[S₂Ox ] for runs 1, 5, 6, and 7 will give a slope of-y. b. Perform the graphing exercises listed above and determine the values of x and y. Insert your graphs from Excel here. Log (Time) vs Log [I] L 1.75 1.8 1.85 1.9 1.95 y=-1.7303x+1.7485 R=0.766 1.6 1.65 0.2 0.4 0.6 .0.8 1 1.2 1.4 -1.6 -1.8 D Log (Time) Log (time) vs. log [S208^2-] 0.5 -0.5 y=-0.8502x-0.0374 R² = 0.9882 -1.5 -25 2 14 1.52 -1.7 25 log (Time) 3. Based on your answers to a and b and the information in the procedure section, write down a mechanism consistent with your results and indicate which step is the rate determining step. 4. Did the copper (II) sulfate catalyze the reaction? Explain your answer.
log [S208^2-] (mol/L) Log In] mol/L a. Assuming the rate expression for this system is in the form, rate - k[I]*[S₂O,²], it should be possible to determine the values of x and y from the data obtained. Show why a plot of log(time) vs log[I] for runs 1-4 will give a slope of -x and log(time) vs. log[S₂Ox ] for runs 1, 5, 6, and 7 will give a slope of-y. b. Perform the graphing exercises listed above and determine the values of x and y. Insert your graphs from Excel here. Log (Time) vs Log [I] L 1.75 1.8 1.85 1.9 1.95 y=-1.7303x+1.7485 R=0.766 1.6 1.65 0.2 0.4 0.6 .0.8 1 1.2 1.4 -1.6 -1.8 D Log (Time) Log (time) vs. log [S208^2-] 0.5 -0.5 y=-0.8502x-0.0374 R² = 0.9882 -1.5 -25 2 14 1.52 -1.7 25 log (Time) 3. Based on your answers to a and b and the information in the procedure section, write down a mechanism consistent with your results and indicate which step is the rate determining step. 4. Did the copper (II) sulfate catalyze the reaction? Explain your answer.
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section11.1: Reaction Rate
Problem 11.3CE
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Can you please help me and explain how I would find a mechanism consistent, using my results. Help with number 5.
![log [S208^2-] (mol/L)
Log In] mol/L
a. Assuming the rate expression for this system is in the form, rate - k[I]*[S₂O,²],
it should be possible to determine the values of x and y from the data obtained.
Show why a plot of log(time) vs log[I] for runs 1-4 will give a slope of -x and
log(time) vs. log[S₂Ox ] for runs 1, 5, 6, and 7 will give a slope of-y.
b. Perform the graphing exercises listed above and determine the values of x and y.
Insert your graphs from Excel here.
Log (Time) vs Log [I]
L
1.75
1.8
1.85
1.9
1.95
y=-1.7303x+1.7485
R=0.766
1.6
1.65
0.2
0.4
0.6
.0.8
1
1.2
1.4
-1.6
-1.8
D
Log (Time)
Log (time) vs. log [S208^2-]
0.5
-0.5
y=-0.8502x-0.0374
R² = 0.9882
-1.5
-25
2
14
1.52
-1.7
25
log (Time)
3. Based on your answers to a and b and the information in the procedure section, write down a
mechanism consistent with your results and indicate which step is the rate determining step.
4. Did the copper (II) sulfate catalyze the reaction? Explain your answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98788fff-5d55-4f08-bd33-832b3c76eea7%2F8a3b5ef2-4ec1-45cb-be54-15634329063d%2Ft01nnvb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:log [S208^2-] (mol/L)
Log In] mol/L
a. Assuming the rate expression for this system is in the form, rate - k[I]*[S₂O,²],
it should be possible to determine the values of x and y from the data obtained.
Show why a plot of log(time) vs log[I] for runs 1-4 will give a slope of -x and
log(time) vs. log[S₂Ox ] for runs 1, 5, 6, and 7 will give a slope of-y.
b. Perform the graphing exercises listed above and determine the values of x and y.
Insert your graphs from Excel here.
Log (Time) vs Log [I]
L
1.75
1.8
1.85
1.9
1.95
y=-1.7303x+1.7485
R=0.766
1.6
1.65
0.2
0.4
0.6
.0.8
1
1.2
1.4
-1.6
-1.8
D
Log (Time)
Log (time) vs. log [S208^2-]
0.5
-0.5
y=-0.8502x-0.0374
R² = 0.9882
-1.5
-25
2
14
1.52
-1.7
25
log (Time)
3. Based on your answers to a and b and the information in the procedure section, write down a
mechanism consistent with your results and indicate which step is the rate determining step.
4. Did the copper (II) sulfate catalyze the reaction? Explain your answer.
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