Rank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. Explanation Check Х (Choose one) OH (Choose one) OCH3 (Choose one) OH (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center
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- Please draw out fully do not use abbreviations such as CO2Me i don't know how to draw it[Review Topics] [References] Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C CH3 H2O NaOH • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Nat, I', in your answer. • In cases where there is more than one answer, just draw one. C opy aste C. Previous Next Email Instructor Save and Ex Cengage Learning | Cengage Technical Support 5:48 PI 82°F 3/28/20Which reaction or statement regarding nucleophilic substitutions is incorrect? A) C₁ + 2 H2O ноттон + 2 HCI B) ta CI+MeOH to + HCI C) D) The rate-limiting step in SN1 reactions is the initial step, loss of the leaving group. Nucleophilic substitution reactions that follow second-order kinetics involve complete inversion of configuration.
- 4. Complete the phrases with one or more of the following terms: SNI, SN2, E1, E2. a) The reaction takes place in two or more steps. b) The reaction goes through a carbocation. c) The rate determining step has two reactants. d) The rate is independent of the concentration of nucleophile or base. e) Zaitsev's rule is often applicable to the products..Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. H3C HCI / H2O `NH2 reflux • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na", I, in your answer. • In cases where there is more than one answer, just draw one. opy aste Previous NextPlease help answer the attached question...thank you!
- McLafferty Rearrangement: Label alpha (), beta (), and gamma () on the molecule. Draw mechanismarrows to describe the process of the rearrangement. What functional group is lost during the rearrangement? What new functional group is made from the ketone/aldehyde you started with? What stabilizing chemical theory causes (allows) rearrangement to happen?For each pair of compounds determine which will undergo electrophilic substitution faster. (d) NO2 (9) SCH, (e) OH (h) HO15)
- [Review Topics] [References] Acyl transfer (nucleophilic substitution at carbonyl) reactions proceed in two stages via a "tetrahedral intermediate." Draw the tetrahedral intermediate as it is first formed in the following reaction. %3D H3C CH3 HO-CH3 • You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • Do not include counter-ions, e.g., Na*, I', in your answer. • In cases where there is more than one answer, just draw one. C P. opy Bste C. Previous Next Email Instructor Save and Exit Cengage Learning | Cengage Technical Support 5:50 PM arch 82°F 3/28/2022[Review Topics] [References] Devise a synthesis of butane using one of the starting materials and any of the reagents below using the fewest steps possible. If you need fewer than the 3 steps allowed, enter "none" for reagents in the remaining unused steps. Starting materials HCECH HOEC-CH, 1 Reagents 2 a Nanhbinh(D) b NaOH/H₂O c iodomethane Starting material Reagent for step 1 Reagent for step 2 Reagent for step 3 Submit Answer HCEC-CH₂CH₂ 3 diodoethane e 1-bromopropane. f 2-bromopropane Retry Entire Group HCEC-CH₂CH₂CH₂CH₂ 4 g 1-bromo-3-methylbutane h t-butyl bromide i H₂/Pd on carbon CH₂ HCEC-C-CH₂ H 5 9 more group attempts remaining KHINH (1) CH₂ HC=C-C-CH₂ CH₂ jH₂ Lindlar catalyst I Na/NH₂ (D 6 Previous Email Instructor Next Save and ExitAdd the necessary reagents and reaction conditions above and below the arrow in this organic reaction.