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NH3 a) II, I, III, IV, V b) II, III, I, V, IV 15. Put the following compounds in the order of increasing acidity (least first). CHA H₁₂O 1pka: 51 11pka=38 111 pra= 15.7 IV. HCI HF Pka= = 3.2 Vp8a=-7 c) I, III, II, V, IV a), II, III, IV, V The correct sequence of the ions shown, in order of increasing basicity, is: 16. A) CH3CH2: < CH2=CH: < HC=C:\ B) CH3CH2: C) HC=C: D) CH2=CH: E) HC=C: < HC=C: < CH2=CH: CH3CH2:1 < < HC=C: < < CH2=CH: < CH2=CH: CH3CH 2: CH3CH2: Hybridization 3 Sp> sp²> sp³. 21 = SH Sp² H I-U-I H-C - C-H -I H-CEC Sp Carbanion hybridization Sp Sp² Sp³ most stable least stable carbcation hybridization SP least table + 503 6 most Stable Sp 3

NH3 a) II, I, III, IV, V b) II, III, I, V, IV 15. Put the following compounds in the order of increasing acidity (least first). CHA H₁₂O 1pka: 51 11pka=38 111 pra= 15.7 IV. HCI HF Pka= = 3.2 Vp8a=-7 c) I, III, II, V, IV a), II, III, IV, V The correct sequence of the ions shown, in order of increasing basicity, is: 16. A) CH3CH2: < CH2=CH: < HC=C:\ B) CH3CH2: C) HC=C: D) CH2=CH: E) HC=C: < HC=C: < CH2=CH: CH3CH2:1 < < HC=C: < < CH2=CH: < CH2=CH: CH3CH 2: CH3CH2: Hybridization 3 Sp> sp²> sp³. 21 = SH Sp² H I-U-I H-C - C-H -I H-CEC Sp Carbanion hybridization Sp Sp² Sp³ most stable least stable carbcation hybridization SP least table + 503 6 most Stable Sp 3

Introductory Chemistry For Today
Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.15E
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(ME EX2) Problems 15-16 Could you please explain problems 15 through 16 to me in detail, step by step? Thank you so much! If necessary, please color-code them for me. 

NH3 a) II, I, III, IV, V b) II, III, I, V, IV 15. Put the following compounds in the order of increasing acidity (least first). CHA H₁₂O 1pka: 51 11pka=38 111 pra= 15.7 IV. HCI HF Pka= = 3.2 Vp8a=-7 c) I, III, II, V, IV a), II, III, IV, V The correct sequence of the ions shown, in order of increasing basicity, is: 16. A) CH3CH2: < CH2=CH: < HC=C:\ B) CH3CH2: C) HC=C: D) CH2=CH: E) HC=C: < HC=C: < CH2=CH: CH3CH2:1 < < HC=C: < < CH2=CH: < CH2=CH: CH3CH 2: CH3CH2: Hybridization 3 Sp> sp²> sp³. 21 = SH Sp² H I-U-I H-C - C-H -I H-CEC Sp Carbanion hybridization Sp Sp² Sp³ most stable least stable carbcation hybridization SP least table + 503 6 most Stable Sp 3
Transcribed Image Text:NH3 a) II, I, III, IV, V b) II, III, I, V, IV 15. Put the following compounds in the order of increasing acidity (least first). CHA H₁₂O 1pka: 51 11pka=38 111 pra= 15.7 IV. HCI HF Pka= = 3.2 Vp8a=-7 c) I, III, II, V, IV a), II, III, IV, V The correct sequence of the ions shown, in order of increasing basicity, is: 16. A) CH3CH2: < CH2=CH: < HC=C:\ B) CH3CH2: C) HC=C: D) CH2=CH: E) HC=C: < HC=C: < CH2=CH: CH3CH2:1 < < HC=C: < < CH2=CH: < CH2=CH: CH3CH 2: CH3CH2: Hybridization 3 Sp> sp²> sp³. 21 = SH Sp² H I-U-I H-C - C-H -I H-CEC Sp Carbanion hybridization Sp Sp² Sp³ most stable least stable carbcation hybridization SP least table + 503 6 most Stable Sp 3
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