Quantitative calculation questions: 1. Liquid ammonia (boiling point = -33.43°C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat 25.0 g of NH3(1) from -65.0°C to -12.0°C? Specific heat capacity, NH3(1): 4.7 J/(g K) Specific heat capacity, NH3(g): 35.1 J/(g K) Heat of vaporization: 23.3 kJ/mol Molar mass, M: 17.0 g/mol A) 5.5 kJ B) 6.3 kJ C) 57 kJ D) 340 kJ E) 590 kJ Answer: C

Chemistry: Matter and Change
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Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter15: Energy And Chemical Change
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Quantitative calculation questions:
1. Liquid ammonia (boiling point = -33.43°C) can be used as a refrigerant and heat transfer
fluid. How much energy is needed to heat 25.0 g of NH3(1) from -65.0°C to -12.0°C?
Specific heat capacity, NH3(1):
4.7 J/(g K)
Specific heat capacity, NH3(g):
35.1 J/(g K)
Heat of vaporization:
23.3 kJ/mol
Molar mass, M:
17.0 g/mol
A) 5.5 kJ
B) 6.3 kJ
C) 57 kJ
D) 340 kJ
E) 590 kJ
Answer: C
Transcribed Image Text:Quantitative calculation questions: 1. Liquid ammonia (boiling point = -33.43°C) can be used as a refrigerant and heat transfer fluid. How much energy is needed to heat 25.0 g of NH3(1) from -65.0°C to -12.0°C? Specific heat capacity, NH3(1): 4.7 J/(g K) Specific heat capacity, NH3(g): 35.1 J/(g K) Heat of vaporization: 23.3 kJ/mol Molar mass, M: 17.0 g/mol A) 5.5 kJ B) 6.3 kJ C) 57 kJ D) 340 kJ E) 590 kJ Answer: C
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