Chapter 20, Problem 36P

To determine

The magnetic field protons produced.

Answer to Problem 36P

  $2.4\times {10}^{-17}$ T

Explanation of Solution

Given:

Rate of stream of protons is $1.5\times {10}^9$ protons/sec

Formula used:

The current and magnetic field are

  $I=\frac{Q}{t}$ and $B=\frac{{\mu }_{0}I}{2\pi r}$

Calculation:

From $I=\frac{Q}{t}$

  $Q=n\times e$

Here,

e is the charge on one proton.

n is number of proton

Substituting the values,

  $\begin{array}{c}I=\frac{1.5\times {10}^9\times 1.6\times {10}^{-19}}{1}\\ =2.4\times {10}^{-10}\text{A}\end{array}$

From, $B=\frac{{\mu }_{0}I}{2\pi r}$

  $B=\frac{4\pi \times {10}^{-7}\times 2.4\times {10}^{-10}}{2\pi \times 2}=2.4\times {10}^{-17}\text{T}$