Concept explainers
The magnitude and direction of electric field for the electron to follow a straight path
Answer to Problem 60P
The magnitude of electric field is
Explanation of Solution
Given:
The radius of circular path is
The magnetic field intensity B = 0.566 T
Formula used:
The velocity of the proton when it moves in a circular path is
Charge on proton is
Mass of proton is
Calculation:
The force due to magnetic field is perpendicular to the magnetic field. Hence for a straight-line path the force due to electric field should equal and opposite to that due to magnetic field
Therefore the formula for electric field is
This electric field is perpendicular to the magnetic field and velocity .
Substituting the given values,
Conclusion:
Thus, the magnitude of electric field is
Chapter 20 Solutions
Physics: Principles with Applications
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