Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
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Chapter 20, Problem 86GP
To determine

Current in the wires.

Expert Solution & Answer
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Answer to Problem 86GP

Current in the wires is 8.4 A

Explanation of Solution

Given:

Diameter of two long straight aluminum wires is 0.50 mm .

Length of the string is 0.50 m and the angle of suspension with the vertical is 3°

Formula used:

Magnetic force is calculated as

  F=μ0I1I22d2l2

Calculation:

Forces experienced by each wire is shown as below,

  Physics: Principles with Applications, Chapter 20, Problem 86GP

Since the net force in both horizontal and vertical direction remains constant. Thus,

  FB=FTsinθFTcosθ=mgFT=mgcosθFB=mgcosθsinθ=mg tanθ=ρAlπrAl2Lg tanθ

The magnetic force is also equal to

  μ0I22SL=ρAlπrAl2Lg tanθI=2SρAlπrAl2Lg tanθμ0LI=2π[2(0.50 m)sin3°](2700 kg/m3)π(2.5×104 m)2(9.8 m/s2)tan3°(4π×107 Tm/A)=8.4 A

Conclusion:

Thus, the current in the wires is 8.4 A

Chapter 20 Solutions

Physics: Principles with Applications

Ch. 20 - Prob. 11QCh. 20 - Prob. 12QCh. 20 - 13. Explain why a strong magnet held near a CRT...Ch. 20 - Prob. 14QCh. 20 - Prob. 15QCh. 20 - Prob. 16QCh. 20 - Prob. 17QCh. 20 - If a moving charged particle is deflected sideways...Ch. 20 - Prob. 19QCh. 20 - Prob. 20QCh. 20 - Prob. 21QCh. 20 - Prob. 22QCh. 20 - Prob. 23QCh. 20 - Why will either pole of a magnet attract an...Ch. 20 - Prob. 25QCh. 20 - Prob. 26QCh. 20 - Prob. 27QCh. 20 - Prob. 28QCh. 20 - Prob. 29QCh. 20 - Prob. 30QCh. 20 - Prob. 31QCh. 20 - Prob. 1PCh. 20 - Prob. 2PCh. 20 - A 240-m length of wire stretches between two...Ch. 20 - Prob. 4PCh. 20 - Prob. 5PCh. 20 - Prob. 6PCh. 20 - Prob. 7PCh. 20 - Prob. 8PCh. 20 - Prob. 9PCh. 20 - Prob. 10PCh. 20 - Prob. 11PCh. 20 - Find the direction of the force on a negative...Ch. 20 - Prob. 13PCh. 20 - Prob. 14PCh. 20 - Prob. 15PCh. 20 - Prob. 16PCh. 20 - Prob. 17PCh. 20 - Prob. 18PCh. 20 - Prob. 19PCh. 20 - Prob. 20PCh. 20 - Prob. 21PCh. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - Prob. 47PCh. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - A circular coil 12.0 cm in diameter and containing...Ch. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - Prob. 62PCh. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67GPCh. 20 - Prob. 68GPCh. 20 - Prob. 69GPCh. 20 - Prob. 70GPCh. 20 - Prob. 71GPCh. 20 - Prob. 72GPCh. 20 - Prob. 73GPCh. 20 - Prob. 74GPCh. 20 - Prob. 75GPCh. 20 - Prob. 76GPCh. 20 - Prob. 77GPCh. 20 - Prob. 78GPCh. 20 - Prob. 79GPCh. 20 - Prob. 80GPCh. 20 - Prob. 81GPCh. 20 - Prob. 82GPCh. 20 - Prob. 83GPCh. 20 - Prob. 84GPCh. 20 - Prob. 85GPCh. 20 - Prob. 86GPCh. 20 - Prob. 87GP
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