Chapter 20, Problem 66P

To determine

The permeability of the field strength

Answer to Problem 66P

  $\mu =2.7\times {10}^{-5}{\text{N/m}}^{\text{2}}$

Explanation of Solution

Given:

Length of solenoid is 38 cm.

Number of turns are 640.

Magnetic field is 2.2 T.

Current is 48 A.

Formula used:

Magnetic field is,

  $B=\frac{{\mu }_{}NI}{L}$

Here, N is the number of turns, I is current and L is length

Calculation:

From $B=\frac{{\mu }_{}NI}{L}$

  $\mu =\frac{BL}{NI}$

  $\mu =\frac{2.2\times 0.38}{640\times 48}=2.7\times {10}^{-5}{\text{N/m}}^{\text{2}}$