A circular coil 12.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 5.50 x 10-5T and points into the Earth at an angle of 56.0° below a line pointing due north. If a 7.20-A clockwise current passes through the coil, (a) determine the torque on the coil, and (b) which edge of the coil rises up: north, east, south, or west?
(a) To Determine:
The torque on the coil ()
Answer to Problem 54P
Solution:
The torque on the coil ()is .
Explanation of Solution
Given Info:
The diameter d of the coil 12 cm or 0.12 m
The number of loops N is 9.
The current I pass through the coil is 7.20 A.
The Earth’s magnetic field B is .
The angle between magnetic field and area vector is (900 -56.00)
The formula to calculate the torque is
• ‘ ’ is the torque.
• ‘N, is the Number of turns of coil.
• ‘d’ is the diameter of coil.
• ‘B’ is the Earth’s magnetic field.
Substitute 9 for ‘N’, 7.20A for ‘I’, 0.12m for ‘d’ and for ‘B’, to find
(b) To Determine:
The direction of coil rise.
Answer to Problem 54P
Solution:
The coil rises up towards north.
Explanation of Solution
The torque is positive i.e. it is directed outward to the plane and magnetic field is pointing into the Earth below a line point due north. According to right hand rule the coil will rise up in north direction.
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