Concept explainers
The current required to give full scale deflection in galvanometer.
Answer to Problem 53P
Solution:
Current,
Explanation of Solution
Given:
that initially galvanometer gives a full-scale deflection by 0.53µA current in its coil at a magnetic field. field drops to 0.76of its initial value.
Formula used:
Angular deflection of a galvanometer is given by
……….. (eq.1)
Where,
N → No of turns
I → Current through Coil
A → Area of loop
B → Field strength of magnet
k → spring constant of galvanometer
Calculation:
Given that initially galvanometer gives a full-scale deflection by 0.53µA current in its coil at a magnetic field. Equation-1 for this case can be written as
……….. (eq.2)
Now the field drops to 0.76 of its initial value. Let I be the current required for full scale deflection in this case. Then equation for this can be written as
……….. (eq.3)
Dividing eqn.3 by eqn.2 gives
Therefore,
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Physics: Principles with Applications
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