a) Interpretation: How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown. Concept introduction: The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H 2 /Pd. To show: How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Question

Which of the structures below is (4R)-4ethyl-2,4- dimethylcyclohexan-1-one?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Which of the structures below is (4R)-4ethyl-2,4- dimethylcyclohexan-1-one?

Which structure is most correct for (2E)-but-2-en-1,4-diol? OH HO OH H,C. CH, HO. H,C HO OH HO

When 2-pentene is treated with Cl, in methanol, three products are formed. Account for the formation of each product (you need not explain their relative percentages). CI OCH3 H,CO CI CI CI Cle CH;CHCHCH,CH, + CH;CHCHCH,CH3 + CH,CHČHCH,CH, CH;OH CH;CH=CHCH,CH, 50% 35% 15%

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 5

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Answer 6

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Answer 7

Chapter 19.9, Problem 13P

Interpretation Introduction

a)

Interpretation:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is to be reduced without affecting the carbonyl group. This reduction can be carried out using H₂/Pd.

To show:

How to prepare 4-methylpentan-2-one from 4-methyl-3-pentene-2-one.

Answer 8

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Answer 9

Interpretation Introduction

b)

Interpretation:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The carbonyl group in a unsaturated ketone can be reduced to –CH₂ without affecting the double bond by treating it with hydrazine in the presence of KOH (Wolf-Kishner reduction).

To show:

How to prepare 2-methylpent-2-ene from 4-methyl-3-pentene-2-one.

Answer 10

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Answer 11

Interpretation Introduction

c)

Interpretation:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one is to be shown.

Concept introduction:

The double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H₂/Pd. The carbonyl group of the saturated ketone formed can be converted to –CH₂ group by Wolff-Kishner reduction.

To show:

How to prepare 2-methylpentane from 4-methyl-3-pentene-2-one.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 15

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 16

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 17

Trending nowThis is a popular solution!

Answer 18

Trending nowThis is a popular solution!

Answer 19

Trending nowThis is a popular solution!

Answer 20

Trending now

Answer 21

This is a popular solution!

Answer 22

See solution

Check out sample textbook solution

Answer 23

Ch. 19.1 - Prob. 1P Ch. 19.1 - Draw structures corresponding to the following...Ch. 19.2 - Prob. 3P Ch. 19.2 - How would you carry out the following reactions?...Ch. 19.4 - Treatment of an aldehyde or ketone with cyanide...Ch. 19.4 - p-Nitrobenzaldehyde is more reactive toward...Ch. 19.5 - Prob. 7P Ch. 19.5 - The oxygen in water is primarily (99.8) 16O, but...Ch. 19.6 - Prob. 9P Ch. 19.8 - Show the products you would obtain by...

Solution Summary: The author explains how the double bond in an unsaturated ketone is reduced without affecting the carbonyl group by treating it with H 2 /Pd.

Chapter 19 Solutions