
a)
Interpretation:
The product of the Wolff-Kishner reduction reaction shown is to be given. The electron-pushing mechanism, beginning from the hydrazone intermediate is to be provided.
Concept introduction:
In Wolff-Kishner reduction
To give:
The product of the Wolff-Kishner reduction reaction shown.
To provide:
The electron-pushing mechanism, beginning from the hydrazone intermediate.

Answer to Problem 38MP
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism for the formation of the alkane, beginning from the hydrazone intermediate, is given below.
Explanation of Solution
The hydroxide ion from KOH abstracts a weakly acidic H from –NH2 of the hydrazone of isopropyl phenyl ketone to yield a carbanion which picks up a proton to yield a neutral intermediate. Deprotonation of the remaining hydrogen on N by the hydroxide ion occurs with the eliminartion of nitrogen to yield another carbanion which is protonated to give the alkane, ethyl benzene, as the product.
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism, beginning from the hydrazone intermediate is given below.
b)
Interpretation:
The product of the Wolff-Kishner reduction reaction shown is to be given. The electron-pushing mechanism, beginning from the hydrazone intermediate is to be provided.
Concept introduction:
In Wolff-Kishner reduction aldehydes and ketones react with hydrazine in the presence of a base to yield alkanes. First a hydrazone is formed which is then converted into an alkane.
To give:
The product of the Wolff-Kishner reduction reaction shown.
To provide:
The electron-pushing mechanism the formation of the alkane beginning from the hydrazone intermediate.

Answer to Problem 38MP
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism the formation of the alkane, beginning from the hydrazone intermediate, is given below.
Explanation of Solution
The hydroxide ion from KOH abstracts a weakly acidic H from –NH2 of the hydrazone of diethyl ketone to yield a carbanion which picks up a proton to yield a neutral intermediate. Deprotonation of the remaining hydrogen on N by the hydroxide ion occurs with the eliminartion of nitrogen to yield another carbanion which is protonated to give the alkane, n-pentane, as the product.
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism, beginning from the hydrazone intermediate is given below.
c)
Interpretation:
The product of the Wolff-Kishner reduction reaction shown is to be given. The electron-pushing mechanism, beginning from the hydrazone intermediate is to be provided.
Concept introduction:
In Wolff-Kishner reduction aldehydes and ketones react with hydrazine in the presence of a base to yield alkanes. First a hydrazone is formed which is then converted into an alkane.
To give:
The product of the Wolff-Kishner reduction reaction shown.
To provide:
The electron-pushing mechanism the formation of the alkane beginning from the hydrazone intermediate.

Answer to Problem 38MP
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism the formation of the alkane, beginning from the hydrazone intermediate, is given below.
Explanation of Solution
The hydroxide ion from KOH abstracts a weakly acidic H from –NH2 of the hydrazone of the ketone to yield a carbanion which picks up a proton to yield a neutral intermediate. Deprotonation of the remaining hydrogen on N by the hydroxide ion occurs with the eliminartion of nitrogen to yield another carbanion which is protonated to give the alkane as the product.
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism, beginning from the hydrazone intermediate is given below.
d)
Interpretation:
The product of the Wolff-Kishner reduction reaction shown is to be given. The electron-pushing mechanism, beginning from the hydrazone intermediate is to be provided.
Concept introduction:
In Wolff-Kishner reduction aldehydes and ketones react with hydrazine in the presence of a base to yield alkanes. First a hydrazone is formed which is then converted into an alkane.
To give:
The product of the Wolff-Kishner reduction reaction shown.
To provide:
The electron-pushing mechanism, beginning from the hydrazone intermediate.

Answer to Problem 38MP
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism for the formation of the alkane beginning from the hydrazone intermediate, is given below.
Explanation of Solution
The hydroxide ion from KOH abstracts a weakly acidic H from –NH2 of the hydrazone of ketone to yield a carbanion which picks up a proton to yield a neutral intermediate. Deprotonation of the remaining hydrogen on N by the hydroxide ion occurs with the eliminartion of nitrogen to yield another carbanion which is protonated to give the alkane as the product.
The product of the Wolff-Kishner reduction reaction shown is
The electron-pushing mechanism for the formation of the alkane beginning from the hydrazone intermediate, is given below.
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Chapter 19 Solutions
Organic Chemistry
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- (2 pts) Why is O2 more stable as a diatomic molecule than S2?arrow_forwardDraw the Lewis structure for the polyatomic phosphite (PO¾³¯) a anion. Be sure to include all resonance structures that satisfy the octet rule. C I A [ ]¯arrow_forwardDecide whether these proposed Lewis structures are reasonable. proposed Lewis structure Is the proposed Lewis structure reasonable? Yes. :0: Cl C C1: 0=0: : 0 : : 0 : H C N No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* ☐ Yes. No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* Yes. ☐ No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | * If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0".arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningEBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT


