(a)
Interpretation:
The terms that apply for
Concept Introduction:
Free
(b)
Interpretation:
The terms that apply for
Concept Introduction:
Free amine is the one that has nitrogen atom bonded to three other atoms and a lone pair of electrons is present on it. Deprotonated base is the one that can accept a hydrogen ion. Due to the lone pair of electrons present on the nitrogen atom in amine, it can also be known as deprotonated base. Free base is the one that has a more electronegative atom which can act as a proton acceptor. Amine has a nitrogen atom which can accept a hydrogen ion. Hence, amine can be a proton acceptor. Protonated base is the one in which the nitrogen atom in the amine has four bonds. The fourth bond formed is a coordinate covalent bond. The formed species has a positive charge on it.
(c)
Interpretation:
The terms that apply for
Concept Introduction:
Free amine is the one that has nitrogen atom bonded to three other atoms and a lone pair of electrons is present on it. Deprotonated base is the one that can accept a hydrogen ion. Due to the lone pair of electrons present on the nitrogen atom in amine, it can also be known as deprotonated base. Free base is the one that has a more electronegative atom which can act as a proton acceptor. Amine has a nitrogen atom which can accept a hydrogen ion. Hence, amine can be a proton acceptor. Protonated base is the one in which the nitrogen atom in the amine has four bonds. The fourth bond formed is a coordinate covalent bond. The formed species has a positive charge on it.
(d)
Interpretation:
The terms that apply for
Concept Introduction:
Free amine is the one that has nitrogen atom bonded to three other atoms and a lone pair of electrons is present on it. Deprotonated base is the one that can accept a hydrogen ion. Due to the lone pair of electrons present on the nitrogen atom in amine, it can also be known as deprotonated base. Free base is the one that has a more electronegative atom which can act as a proton acceptor. Amine has a nitrogen atom which can accept a hydrogen ion. Hence, amine can be a proton acceptor. Protonated base is the one in which the nitrogen atom in the amine has four bonds. The fourth bond formed is a coordinate covalent bond. The formed species has a positive charge on it.
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Chapter 17 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
- As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will its major product: 2,0° with a new C-C bond as If this reaction will work, draw the major organic product or products you would expect in the drawing aree below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and desh bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new C-C bond, just check the box under the drawing area and leave it blank.arrow_forwardwrite the mechanism of the nucleophilic acyl substitution reaction, please give an examplearrow_forwardThe compound in the figure is reacted with 10 n-butyllihium, 2° propanone, and 3º H2O. Draw and name the products obtained. SiMe3arrow_forward
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