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Interpretation:
IUPAC names has to be assigned for the eight isomeric primary
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Isomers are the compounds that have same molecular formula but different structural formula. The main difference lies in the way the atoms are arranged in the structure. Isomers have different chemical and physical properties even when they have same molecular formula. This is known as Isomerism.
If there is difference only in the connectivity of the atoms in the molecule, then it is known as constitutional isomerism. The isomers are known as constitutional isomers. They will have same molecular formula and same
- Longest carbon chain has to be identified that is attached to nitrogen atom.
- Suffix “-e” in name of the parent chain
alkane is replaced by “-amine”. - Numbering of the carbon chain is done from the end that is near the nitrogen atom.
- Point of attachment of the nitrogen atom in the carbon chain is indicated by a number before the parent chain name.
- In case if substituents are present, then the identity and location of substituents are appended to the front in the parent chain name.
If the compound contains two amine groups, then the suffix “-e” is replaced by diamine. Tertiary and secondary amines are named as N-substituted primary amines.
Common name for amine is given in a single word. Primary amine is named as alkylamine. Secondary amine is named as alkylalkylamine. Tertiary amine is named as alkylalkylalkylamine.
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Chapter 17 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- Nonearrow_forwardIn the solid state, oxalic acid occurs as a dihydrate with the formula H2C2O4 C+2H2O. Use this formula to calculate the formula weight of oxalic acid. Use the calculated formula weight and the number of moles (0.00504mol) of oxalic acid in each titrated unknown sample recorded in Table 6.4 to calculate the number of grams of pure oxalic acid dihydrate contained in each titrated unknown sample.arrow_forward1. Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their (2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these orbitals from the two atoms forming a homonuclear л-bond. Which element would have a stronger bond, and why? (4 points)arrow_forward
- Write the reaction and show the mechanism of the reaction. Include the mechanism for formation of the NO2+ 2. Explain, using resonance structures, why the meta isomer is formed. Draw possible resonance structures for ortho, meta and para.arrow_forwardNonearrow_forward3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward
- 9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward
- 5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
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