(a)
Interpretation:
Chemical equation for the conversion of given
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(a)
Explanation of Solution
Given carboxylic acid salt is calcium propanoate. The structure of calcium propanoate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
(b)
Interpretation:
Chemical equation for the conversion of given carboxylic acid salt to its parent carboxylic acid using
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(b)
Explanation of Solution
Given carboxylic acid salt is sodium lactate. The structure of sodium lactate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
(c)
Interpretation:
Chemical equation for the conversion of given carboxylic acid salt to its parent carboxylic acid using
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(c)
Explanation of Solution
Given carboxylic acid salt is magnesium succinate. The structure of magnesium succinate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
(d)
Interpretation:
Chemical equation for the conversion of given carboxylic acid salt to its parent carboxylic acid using
Concept Introduction:
The name of the carboxylic acid itself implies that it is acidic. Addition of carboxylic acid to water results in ionization. Hydrogen ion transfer occurs from carboxylic acid to water and hydronium ion is formed. Carboxylate ion is also formed due to the loss of hydrogen ion from carboxylic acid.
Carboxylate ion is the negative ion which is formed when one or more acidic protons are lost from carboxylic acid. Similar to carboxylic acid it reacts with strong base to form carboxylic acid salt and water.
Carboxylic acid salts when treated with a strong acid produces carboxylic acid as the product.
Carboxylic acid forms carboxylic acid salt by reacting with a strong base. The general reaction scheme for the formation of carboxylic acid salt is given as shown below,
The reverse of the above reaction is conversion of carboxylic acid salt to carboxylic acid. This is accomplished by using strong acid. The scheme is shown below,
From the above chemical equation it is found that the carboxylic acid salt reacts with strong acid to form carboxylic acid.
(d)
Explanation of Solution
Given carboxylic acid salt is potassium benzoate. The structure of potassium benzoate can be given as shown below,
Carboxylic acid sat is converted to carboxylic acid by reaction with strong acid. In the problem statement it is given that the strong acid is
Chemical equation for the conversion of given carboxylic acid salt to carboxylic acid using hydrochloric acid is written.
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Chapter 16 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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