Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Textbook Question
Chapter 15, Problem 29CTQ
A normal mRNA that reads 5’ -
UGCCAUGGUAAUAACACAUGAGGCCUGAAC- 3’ has an insertion mutation that changes the sequence to 5'
-UGCCAUGGUUAAUAACACAUGAGGCCUGAAC- 3’. Translate the original mRNA and the mutated mRNA, and explain how insertion mutations can have dramatic effects on proteins. (Hint: Be sure to find the initiation site.)
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c) A gene in a bacteria has the following DNA sequences (the promoter sequence is
positioned to the left but is not shown):
5'-CAATCATGGAATGCCATGCTTCATATGAATAGTTGACAT-3'
3'-GTTAGTACCT TACGGTACGAAGTATACTTATCAACTGTA-5'
i) By referring to the codon table below, write the corresponding mRNA transcript and
polypeptide translated from this DNA strand.
2
Second letter
с
A
UUUPhe
UAU
Tyr
UAC.
UGU
UGCJ
UCU)
UCC
UCA
UUG Leu UCG
Cys
UUC
UUA
Ser
UAA Stop UGA Stop A
UAG Stop UGG Trp G
CUU
CÚC
CCU
ССС
CAU
CGU
His
САC
Pro
CC
CỦA
Leu
ССА
CAA
Arg
CGA
CUG J
CCG)
CAG Gin
CGG
AUU
ACU
AAU
Asn
AGU
Ser
AUC le
АСC
АCА
AAC
AAA
AGC.
Thr
JArg
AUA
AGA
AUG Met ACG
AAG Lys
AGG.
GAU
Asp
GUU)
GCU
GCC
GCA
GCG
GGU"
GGC
GGA
GGG
GUC
Val
GUA
GAC
Ala
Gly
GAA
Glu
GAGJ
GUG
ii) If the nucleotide indicated by the highlighted bold letter undergoes a mutation that
resulted in deletion of the C:G base pair, what will be the resulting amino acid sequence
following transcription and translation?
Third letter
DUAG
DUAG
DUAG
A.
First…
Consider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start):
5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’
By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?
What will be the overall anti-codon sequence in tRNA for this mRNA?
5’-GUAGCCUUAUCUAGCGAUCACCGUCCGUAUUACUAGUGGCCAGACUCUUUUCACCAUGUAUAGUUG-3’
Chapter 15 Solutions
Biology 2e
Ch. 15 - Figure 15.11 A scientist splices a eukaryotic...Ch. 15 - Figure 15.13 Errors in splicing are implicated in...Ch. 15 - Figure 15.16 Many antibiotics inhibit bacterial...Ch. 15 - The AUC and AUA codons in mRNA both specify...Ch. 15 - How many nucleotides are in 12 mRNA codons? 12 24...Ch. 15 - Which event contradicts the central dogma of...Ch. 15 - Which subunit of the E. coli polymerase confers...Ch. 15 - The -10 and -35 regions of prokaryotic promoters...Ch. 15 - Three different bacteria species have the...Ch. 15 - Which feature of promoters can be found in both...
Ch. 15 - What transcripts will be most affected by low...Ch. 15 - How do enhancers and promoters differ? Enhancers...Ch. 15 - Which pre-mRNA processing step is important for...Ch. 15 - What processing step enhances the stability of...Ch. 15 - A scientist identifies a pre-mRNA with the...Ch. 15 - The RNA components of ribosomes are synthesized in...Ch. 15 - In any given species, there are at least how many...Ch. 15 - A scientist introduces a mutation that makes the...Ch. 15 - Imagine if there were 200 commonly occurring amino...Ch. 15 - Discuss how degeneracy of the genetic code makes...Ch. 15 - A scientist sequencing itiRNA identifies the...Ch. 15 - If mRNA is complementary to the DNA template...Ch. 15 - In your own words, describe the difference between...Ch. 15 - A fragment of bacterial DNA reads: 3’...Ch. 15 - A scientist observes that a cell has an RNA...Ch. 15 - Chronic lymphocytic leukemia patients often harbor...Ch. 15 - Transcribe and translate the following DNA...Ch. 15 - Explain how single nucleotide changes can have...Ch. 15 - A normal mRNA that reads 5’ -...
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- Template strand of DNA is: 3’ TACATAACCGGGCCCATATCGGCCATTTGC5’. 2a). Following transcription, what is the total number of codons in the mRNA transcript? 2 b). Where is the start codon located in this mRNA transcript? 2c). Following translation of this mRNA transcript, how many amino acids will the proteincontain and identify the amino acids sequence of this gene from a genetic code table*.*Note= using a genetic code tablearrow_forwardGiven the following DNA sequence of the template strand for a given gene: 5' TTTCCGTCTCAGGGCTGAAAATGTTTGCTCATCGAACGC3' Part A ) Write the mRNA that will be transcribed from the DNA sequence above (be sure to label the 5' and 3' ends). Part B ) Use the genetic code to write the peptide sequence translated in a cell from the mRNA in part A. Please use the 3 letter abbreviation for each amino acid. Part C: How would the peptide synthesized in a cell be different if the mRNA was translated in vitro (i.e. not in the cell)?arrow_forwardReferring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –GUACUAAGGAGGUUGUAUGGGUUAGGGG ACAUCAUUUUGA–3′arrow_forward
- Referring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –UUUGGAUUGAGUGAAACGAUGGAUGAAAG AUUUCUCGCUUGA–3′arrow_forwardAs described earlier, DNA damage can cause deletion or insertion of base pairs. If a nucleotide base sequence of a coding region changes by any number of bases other than three base pairs, or multiples of 3, a frameshift mutation occurs. Depending on the location of the sequence change, such mutations can have serious effects. The following synthetic mRNA sequence codes for the beginning of a polypeptide: 5′-AUGUCUCCUACUGCUGACGAGGGAAGGAGGUGGCUUAUC-AUGUUU-3′ First, determine the amino acid sequence of the polypeptide. Then determine the types of mutation that have occurred in the following altered mRNA segments. What effect do these mutations have on the polypeptide products? a. 5′-AUGUCUCCUACUUGCUGACGAGGGAAGGAGGUGGCUUAUCA-UGUUU-3′ b. 5′-AUGUCUCCUACUGCUGACGAGGGAGGAGGUGGCUUAUCAU-GUUU-3′ c. 5′-AUGUCUCCUACUGCUGACGAGGGAAGGAGGUGGCCCUUAUC-AUGUUU-3′ d. 5′-AUGUCUCCUACUGCUGACGGAAGGAGGUGGCUUAUCAU-GUUU-3′arrow_forwardIf an antisense RNA is designed to silence the following mRNA sequence, which of the following antisense oligos (a-d) could be used for this purpose? mRNA sequence: 5' UAGGACUAUUAAGGUACACCCAUU 3' O 5' AUCCUGAUAAUUCCAUGUAAAUAA 3' O 5' AAUGGGUGUACCUUAAUAGUCCUA 3' O 5' UAGGACUAUUAAGGUACACCCAUU 3' O 5' UUACCCACAUGGAAUUAUCAGGAU 3¹arrow_forward
- Given the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'arrow_forwardReferring to the genetic code presented in Figure , give the aminoacids specified by the following bacterial mRNA sequences. Q. 5′ –AUGUUUAAAUUUAAAUUUUGA–3′arrow_forwardMany uridine molecules are inserted into some mitochondrial mRNAs in trypanosomes. The uridine residues come from the poly(U) tail of a donor strand. Nucleoside triphosphates do not participate in this reaction. Propose a reaction mechanism that accounts for these findings. (Hint: Relate RNA editing to RNA splicing.)arrow_forward
- Using the genetic code table provided below, write out the sequence of three different possible mRNA sequences that could encode the following sequence of amino acids: Met-Phe-Cys-Trp-Glu C A G U C UUU Phe UCU Ser UUC Phe UCC Ser UCA Ser UUA Leu UUG Leu UCG Ser CUU Leu CCU Pro CUC Leu CUA Leu CUG Leu CCG A CAU His CGU Arg CCC Pro CAC His CGC Arg UAU Tyr UGU Cys U UAC Tyr UGC Cys C Stop UGA Stop Stop UGG Trp UAA A UAG G CCA Pro CAA Gln Pro CAG AUU lle AUC lle AUA lle AUG Met ACG G 등등 Gln CGA Arg CGG Arg ACU Thr AAU Asn AGU Ser ACC AAC Asn AGC Ser Thr ACA Thr Thr AAA Lys AGA Arg AAG Lys AGG Arg GUU Val GCU Ala GAU Asp GGU Gly GGC Gly GUC Val GCC Ala GAC Asp GUA Val GCA Ala GAA Glu GGA Gly GUG Val GCG Ala GAG Glu GGG Gly U C A G U C A G SUAUarrow_forwardWhat is the sequence of the mRNA transcript that will be produced from the following sequence of DNA? The top strand is the template strand, the bottom strand is the coding strand. 5’ – TCGGGATTAGACGCACGTTGGCATACCTCG – 3’ 3’ – AGCCCTAATCTGCGTGCAACCGTATGGAGC – 5’ Enter the mRNA sequence here (pay close attention to the direction of the molecule!): 5'-_____-3'arrow_forwardThe following four mutations have been discovered in a gene that has more than 60 exons and encodes a very large protein of 2532 amino acids. Indicate which mutation would likely cause a detectable change in the size of the mRNA and/or the size of the protein product. Consider a detectable change to be >10% of the wild-type size. A table of the genetic code is shown below. First letter 0 00 U O A บบบ UUC UUA UUG U CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu >Leu AUU AUC lle AUA AUG Met >Val UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second letter C Ser Pro Thr Ala CAU CAC CAA CAG UAU UGU Tyr UAC UGC UAA Stop UGA UAG Stop UGG AAU AAC AAA AAG A GAU GAC GAA GAG His Gin Asn Lys Asp G Glu CGU CGC CGA CGGJ AGU AGC AGA AGG GGU GGC GGA GGG O AAG576UAG (changes codon 576 from AAG to UAG) Cys Stop Trp O GUG326AUG (changes codon 326 from GUG to AUG) Arg Ser Arg Gly DUAG DUA G DCAG DO AG deletion of codon 779 insertion of 1000 base pairs into the sixth intron (this particular…arrow_forward
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