Genetic Analysis: An Integrated Approach (2nd Edition)
2nd Edition
ISBN: 9780321948908
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Textbook Question
Chapter 14, Problem 26P
Suppose that base substitution mutations sufficient to eliminate the function of the operator regions listed below were to occur. For each case, describe how transcription or life cycle would be affected.
a. lacO mutation in E. coli
b.
c.
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Chapter 14 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
Ch. 14 - 12.1 Bacterial genomes frequently contain groups...Ch. 14 - Transcriptional regulation of operon gene...Ch. 14 - Why is it essential that bacterial cells be able...Ch. 14 - Identify similarities and differences between an...Ch. 14 - The transcription of -galactosidase and permease...Ch. 14 - 12.6 Is attenuation the product of an allosteric...Ch. 14 - The trpL region contains four repeated DNA...Ch. 14 - The CAP binding site in the lac promoter is the...Ch. 14 - What role does cAMP play in transcription of lac...Ch. 14 - How would a cap- mutation that produces an...
Ch. 14 - Explain the circumstances under which attenuation...Ch. 14 - Consider the transcription of genes of the...Ch. 14 - Describe the lytic and lysogenic life cycles of ...Ch. 14 - 12.14 Define antisense RNA, and describe how it...Ch. 14 - 12.15 Attenuation of trp operon transcription is...Ch. 14 - 12.16 In the lac operon, what are the likely...Ch. 14 - Identify which of the following lac operon haploid...Ch. 14 - Prob. 18PCh. 14 - 12.19 List possible genotypes for lac operon...Ch. 14 - Suppose each of the genotypes you listed in parts...Ch. 14 - 12.21 Four independent mutants (mutants A to D)...Ch. 14 - Suppose the lac operon partial diploid...Ch. 14 - Prob. 23PCh. 14 - 12.24 A repressible operon system, like the trp...Ch. 14 - 12.25 What is the likely effect of each of the...Ch. 14 - 12.26 Suppose that base substitution mutations...Ch. 14 - 12.27 Two different mutations affect. Mutant...Ch. 14 - How would mutations that inactivate each of the...Ch. 14 - The bacterial insertion sequence IS 10 uses...Ch. 14 - 12.34 Northern blot analysis is performed on...Ch. 14 - 12.37 The electrophoresis gel shown in part (a) is...Ch. 14 - Prob. 32PCh. 14 - The following hypothetical genotypes have genes A,...Ch. 14 - For an E. coli strain with the lac operongenotype...
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- What would happen if a lysine residue that was normally acetylated was mutated to an arginine? A. There would probably be no affect on transcription B. The nucleosome affected by this mutation would be more likely to be uncondensed C. Genes within or near the nucleosome affected by this mutation would be more likely to be repressed D. RNA Pol II would have an easier time accessing the DNA at or near the affected nucleosome E. B and C are both correctarrow_forwardE. coli has five genes that code for enzymes that make tryptophan. These genes are regulated by a single promoter and transcribed as one long gene. The presence of tryptophan shut down the production of tryptophan by the cell by binding to the repressor. This changes the repressors shape allowing it to bind to DNA operator, blocking RNA polymerase and cutting off the production of tryptophan. a. Describe what woud happen to the operon if some of the cells had a mutation on the repressor, not allowing it to bind with tryptophan. The repressor is described as an allosteric protein. What does this mean? b. Does the tryptophan model demonstrate an inducible or repressible operon? What is your evidence? *arrow_forwardThe following DNA nucleotides are found near the end of a bacterial transcription unit. 3′–AGCATACAGCAGACCGTTGGTCTGAAAAAAGCATACA–5′ a. Mark the point at which transcription will terminate. b. Is this terminator rho independent or rho dependent? c. Draw a diagram of the RNA that will be transcribed from this DNA, including its nucleotide sequence and any secondary structures that form.arrow_forward
- The MRNA for a mammalian peptide that enhances electrolyte transfer to reduce paralysis was spliced then reversed transcribed and the CDNA ligated into a phage and transfected into host bacteria cells. The host then transcribed and translated this. The protein product however was non-functional. What is the most probable reason for this result? A. Absence of post-transcriptional modification in bacterial cells B. Differences in the post-translational mechanisms in eukaryotes and prokaryotes. C. Differences in the translational mechanisms involved in prokaryotes, e.g. 70 S ribosome vs 80S ribosome. D. The mRNA did not contain a promoter region to allow peptide translation. E. Insertion of portions of the phage DNA which added sequences for amino acids changing the function of the protein product.arrow_forwardImagine that mutations occurred in one of the inverted repeat sequences within the rho-independent terminator sequence of a bacterium. What would likely be the consequence of this mutation? Select one: a. Transcription may not be initiated at all. b. Transcription may end prematurely. c. Transcription may be delayed. d. The rho protein won't be able to bind and transcription may not be terminate. e. Transcription may not be terminated and result in much longer RNA.arrow_forwardE. coli has five genes that code for enzymes that make tryptophan. These genes are regulated by a single promoter and transcribed as one long gene. The presence of tryptophan shut down the production of tryptophan by the cell by binding to the repressor. This changes the repressors shape allowing it to bind to DNA operator, blocking RNA polymerase and cutting off the production of tryptophan. a. Describe what would happen to the operon if some of the cells had a mutation on the repressor, not allowing it to bind with tryptophan. The repressor is described as an allosteric protein. What does this mean? b. Does the tryptophan model demonstrate an inducible or repressible operon? What is your evidence?*arrow_forward
- Why might a single base-pair mutation in eukaryotic mRNA be less serious than one in prokaryotic mRNA? a. If the mutation occurs in the 5' end of the start site, it will not affect the gene product. b. If the mutation occurs in the exon, it will not affect the gene product. c. If the mutation occurs in the splice site of a transcript with alternative splicing, only one gene product may affected. O d. If the mutation occurs in the intron or not in the splice site of a transcript with alternative splicing, it will nc affect the gene product. O e. If the mutation occurs in the 3' end of the start site, it will not affect the gene product. OLIE STIC N 1Aarrow_forwardFor the trp operon, determine whether genes will be expressed (on) or silenced (off) given the following: a. Tryptophan levels are high. b. The trp repressor can no longer bind tryptophan.arrow_forwardSelect the events from eukaryotic transcription from the list below and list them below in order, by letter, from earliest to latest during transcription. A. Sigma factor binds 5'TTGACA?' B. Rho separates DNA/RNA hybrid C. TFIID binds TATA Box D. RNA Pol Il binds E. Holoenzyme forms F. Template strand is used to synthesize a 5' to 3' polymer G. Transcript is moved into the cytoplasm H. U1, U2, U4, U5 and U6 sn RNPs bind transcriptarrow_forward
- Listed in parts a through g are some mutations that were found in the 5′ UTR of the trp operon of E. coli. What will the most likely effect of each of these mutations be on the transcription of the trp structural genes? a. A mutation that prevents the binding of the ribosome to the 5′ end of the mRNA 5′ UTR b. A mutation that changes the Trp codons in region 1 of the mRNA 5′ UTR into codons for alanine c. A mutation that creates a stop codon early in region 1 of the mRNA 5′ UTR d. Deletions in region 2 of the mRNA 5′ UTR e. Deletions in region 3 of the mRNA 5′ UTR f. Deletions in region 4 of the mRNA 5′ UTR g. Deletion of the string of adenine nucleotides that follows region 4 in the 5′ UTRarrow_forwardINTERPRET DATA Develop a simple hypothesis that would explain the behavior of each of the following types of mutants in E. coli. Mutant a: The map position of this mutation is in the trp operon. The mutant cells are constitutive; that is, they produce all the enzymes coded for by the trp operon, even if large amounts of tryptophan are present in the growth medium. Mutant b: The map position of this mutation is in the trp operon. The mutant cells do not produce any enzymes coded for by the trp operon under any conditions. Mutant c: The map position of this mutation is some distance from the trp operon. The mutant cells are constitutive; that is, they produce all the enzymes coded for by the trp operon, even if the growth medium contains large amounts of tryptophan.arrow_forwardPlease Explainarrow_forward
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