To analyze:
In the given table, the partial diploid genotypes are tested for the following aspescts:
Complete the following table for production of
Introduction:
In the lac operon, the partial diploids are produced by conjugation between
Based on the studies of structural gene mutations, Jacob, Monod, and Colleagues concluded that lac
These two wild type alleles are always dominant to the mutant type alleles.
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Chapter 14 Solutions
Genetic Analysis: An Integrated Approach (2nd Edition)
- The intermediates A, B, C, D, E, and F all occur in the same biochemical pathway G is the product of the pathway, and mutations 1 through 7 are all G –, meaning that they cannot produce substance G. The following table shows which intermediates will promote growth in each of the mutants. Arrange the intermediates in order of their occurrence in the pathway at which each mutant strain is blocked. A “+” in the table indicates that the strain will grow if given that substance, an “o” means lack of growth.arrow_forwardSchizosaccharomyces pombe, also known as "fission yeast," is a powerful model organism in molecular and cell biology. While performing a genetic screen, you discover an auxotrophic S. pombe strain that is unable to synthesize one or more vitamins. The following table represents the key experiments you performed during your genetic screen. Fill in the table with the outcome of each experiment for your mutant strain (using + for growth and - for no growth). Medium Rich media Minimal media Minimal media + all vitamins Minimal media + all amino acids Growth Wild-type + + + + Mutant + + + > > >arrow_forward18) Based on your knowledge of lactose system in prokaryotes) and considering the following genotypes, complete the table below indicating a "+" where an enzyme is produced and a where no enzyme is produced. Note: Is is a mutant that cannot recognize allolactosearrow_forward
- The intermediates A, B, C, D, E, and F all occur inthe same biochemical pathway. G is the product of thepathway, and mutants 1 through 7 are all G−, meaningthat they cannot produce substance G. The followingtable shows which intermediates will promote growthin each of the mutants. Arrange the intermediates inorder of their occurrence in the pathway, and indicatethe step in the pathway at which each mutant strain isblocked. A + in the table indicates that the strain willgrow if given that substance, an O means lack of growth.SupplementsMutant A B C D E F G1 + + + + + O +2 O O O O O O +3 O + + O + O +4 O + O O + O +5 + + + O + O +6 + + + + + + +7 O O O O + O +arrow_forwardThe enzyme glucose oxidase isolated from the mold Penicillium notatum catalyzes the oxidation of B-D-glucose to D-glucono-6-lactone. The enzyme is highly specific for the B anomer of glucose and does not affect the a anomer. In spite of this specificity, the reaction catalyzed by glucose oxidase is commonly used in a clinical assay for total blood glucose -that is, for solutions consisting of a mixture of B- and a-D-glucose, as well as other sugars present in blood. The oxidation proceeds in the presence of oxygen and forms hydrogen peroxide, in addition to the lactone. A second enzyme, called peroxidase, catalyzes the reaction of hydrogen peroxide with colorless compounds to create a colored product, which is quantified with a simple spectrophotometer. What are the circumstances required to make this possible? Aside from allowing the detection of smaller quantities of glucose, what advantage does glucose oxidase offer over the Fehling's reagent for measuring blood glucose?arrow_forwardThe enzyme glucose oxidase isolated from the mold Penicillium notatum catalyzes the oxidation of β-Dglucose to D-glucono-δ-lactone. This enzyme is highly specific for the β anomer of glucose and does not affect the α anomer. In spite of this specificity, the reaction catalyzed byglucose oxidase is commonly used in a clinical assay for total blood glucose—that is, for solutions consisting of a mixture of β- and α-D-glucose. What are the circumstances required to make this possible? Aside from allowing the detection of smaller quantities of glucose, what advantage does glucose oxidase offer over Fehling’s reagent for measuring blood glucose?arrow_forward
- A unique aquatic plant was discovered from a lagoon in El Nido, Palawan. To determine the protein content of the plant, an adequate amount of the plant extract was acquired, and Bradford assay was performed. Determine the total protein concentration, in µg/mL, of the acquired plant extract. A bovine serum albumin (BSA) stock solution with a concentration of 250 µg/mL was used and mixtures with the following compositions and absorbance readings were prepared: Volume of BSA (mL) Volume of water (mL) Absorbance Tube # at 595 nm 1 0.00 2.00 0.000 2 0.20 1.80 0.112 3 0.40 1.60 0.225 4 0.60 1.40 0.318 5 0.80 1.20 0.432 6 1.00 1.00 0.551 The absorbance reading of the plant extract is 0.275.arrow_forwardWhich gene encodes the enzyme at the upper boxed step in the pathway? Which gene encodes the enzyme at the upper boxed step in the pathway? gene 1 gene 2 gene 3 gene 4arrow_forwardGive only typing answer with explanation and conclusion For the genotype shown below, which best describes the expression of the B-galactosidase gene. I+ Oc Z+ / F’ Is Constitutive Repressed Inducible None of the abovearrow_forward
- Indicate the presence of the the B galactosidase and permease. Please explain and follow the instructions in the picturearrow_forwardI have this strain of e coli. Is P+ o+ Z+ Y+ / I- P+ oC Z- Y+ Will beta-galactosidase and permease be expressed? If they are will they be inducible or constitutive?arrow_forwardThe substrate which was used to investigate the enzymatic activity of wheat bran phosphatase was p-nitrophenyl phosphate. It is converted to p-nitrophenol and inorganic phosphate by this enzyme. P-nitrophenol has a pKa of 7.1 and is colorless, while its conjugate base, p-nitrophenolate has a yellow color. The enzyme assay was performed at pH 5.1 after the 0.5 N KOH is added at the end of each enzyme assay, the pH of the assay mixture is raised to 9.1. Why was the base added?arrow_forward
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning