Explanation Given information: Mass of the bullet = m = 6 g Mass of the block = M = 1 k g Length of the cord = l = 2.2 m θ = 60 0 General impulse-momentum principal, m v 1 + ∑ I m p 1 → 2 = m v 2 Kinetic energy, K . E . = 1 2 m v 2 Potential Energy, P . E . = m g h Calculation: Apply enegy conservation considering the motion of combined bullet and block. v 1 is the velocity just after impact. 1 2 ( m + M ) v 1 2 = ( m + M ) g h → v 1 = 2 g h h = l − l sin θ h = 2.2 m × ( 1 − sin 60 0 ) h = 0.2948 m → v 1 = 29 To determine (b) The impulse imparted by the bullet on the block. To determine (c) The force on the cord immediately after the impact.

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Question

Chapter 13.3, Problem 13.152P

To determine

(a)

The initial speed of the bullet v0.

To determine

(b)

The impulse imparted by the bullet on the block.

To determine

(c)

The force on the cord immediately after the impact.

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Chapter 13.3, Problem 13.151P

Chapter 13.3, Problem 13.153P

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