Explanation Given: Let position 1 be the initial position. r 1 = 0.3 m ( v r ) 1 = 0 , ( v θ ) 1 = 2 m / s v 1 = 2 m / s x 1 = r 1 − l 0 = ( 0.3 − 0.5 ) = − 0.2 m Let position 2 be when r = 0.6 m . r 2 = 0.6 m Now, we need to find ( v r ) 2 , ( v θ ) 2 , v 2 x 2 = r 2 − l 0 = ( 0.6 − 0.5 ) = 0.1 m Conservation of angular momentum: r 1 m ( v θ ) 1 = r 2 m ( v θ ) 2 ( v θ ) 2 = r 1 ( v θ ) 1 r 2 = ( 0

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Forced undamped vibrations

In mechanical engineering, vibration is expressed as the term that occurs due to an object's backward and forward movement about a point of equilibrium. Generally, there are three types of vibrations which are,

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Chapter 13.2, Problem 13.93P

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Radial and transverse components of the velocity of collar when r=0.6 m.

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Chapter 13.2, Problem 13.92P

Chapter 13.2, Problem 13.94P

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Vector Mechanics for Engineers: Dynamics

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Radial and transverse components of the velocity of collar when r = 0.6 m .

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Radial and transverse components of the velocity of collar when r=0.6 m.

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