Explanation Given information: The system is released from rest. A force acting on a particle during a very short time interval but large enough to produce a definite change in momentum is called an impulsive force. Impulse momentum principle for impulsive motion is defined as: m v 1 + ∑ F a v g Δ t = m v 2 Calculation: For block A and C: Apply impulse momentum principle: ↓ m v 1 + ∑ F a v g Δ t = m v 2 Substitute, [ ( m A + m C ) v ] 1 − T Δ t + ( m A + m C ) g Δ t = [ ( m A + m C ) v ] 2 Then, 0 + ( 12 g − T ) ( 0.8 s ) = 12 v → ( 1 ) To determine (b) The force exerted by the cylinder on the platform

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Question

Chapter 13.3, Problem 13.133P

To determine

(a)

The velocity of block B after 0.8 s.

To determine

(b)

The force exerted by the cylinder on the platform

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Chapter 13.3, Problem 13.132P

Chapter 13.3, Problem 13.134P

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Vector Mechanics for Engineers: Dynamics

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