Explanation Given: L 0 = 2 ft L 1 = 3 ft k = 1 l b / in = 12 l b / ft m = W / g = 1.5 / 32.2 = 0.04658 l b . s 2 / ft Let L 1 be taken as initial stretched length of the cord. Let position 1 be the initial position. Let position 2 be the position of the closest approach to the point after the cord has become slack. While the cord is slack there are no horizontal forces acting on the ball, so the velocity remains constant. While the cord is stretched, the only horizontal force acting on the ball is conservative central force, which is due to elastic cord. At the point of closest approach, the velocity of the ball is perpendicular to the radius vector . Conservation of angular momentum: r 1 m v 1 = r 2 m v 2 L 1 v 0 = d v 2 Or: v 2 = L 1 d v 0 Conservation of energy: T 1 To determine (b) Maximum speed of the ball.

Vector Mechanics for Engineers: Dynamics

11th Edition

ISBN: 9780077687342

Author: Ferdinand P. Beer, E. Russell Johnston Jr., Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 13.2, Problem 13.97P

To determine

(a)

Initial speed v0 of the ball.

To determine

(b)

Maximum speed of the ball.

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Chapter 13.2, Problem 13.96P

Chapter 13.2, Problem 13.98P

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