Chapter 12, Problem 15STP

Interpretation Introduction

Interpretation: The number of atoms of oxygen in $2.4\text{m}\text{o}\text{l}\text{o}\text{f}{\text{H}}_2\text{S}{\text{O}}_4$ needs to be determined.

Concept introduction: According to mole concept, in 1 mol of any substance, there are $6.022\times {10}^{22}$ units.

Answer to Problem 15STP

(D) $5.78\times {10}^{24}\text{atoms}$ .

Explanation of Solution

According to mole concept, $\text{1}\text{mole}=6.02\times {10}^{23}$ particles thus, in ${\text{H}}_2\text{S}{\text{O}}_4$ , $\text{1}\text{mole}=6.02\times {10}^{23}$ molecules of ${\text{H}}_2\text{S}{\text{O}}_4$ .

Thus, $\text{2}\text{.4}\text{mole=2}\text{.4×6}{\text{.02×10}}^{\text{23}}$ molecules of ${\text{H}}_2\text{S}{\text{O}}_4$ .

In terms of atoms, $1$ molecule ${\text{H}}_2\text{S}{\text{O}}_4$ has $=4$ atoms of oxygen.

Then, $2.4\times 6.02\times {10}^{23}$ molecules ${\text{H}}_2\text{S}{\text{O}}_4$ have $=4\times 2.4\times 6.02\times {10}^{23}$ atom.

  $=5.8\times {10}^{24}$ atoms of oxygen.

Conclusion

Thus, to calculate the number of particles, Avogadro’s number is used.