Chapter 12.1, Problem 12SSC

Interpretation Introduction

Interpretation:

The partial pressure of gas B in the mixture of gas A and B if total pressure is 1.20 atm and partial pressure of gas A is 0.75 atm needs to be determined.

Concept introduction:

In a gas mixture, each gas component exerts some pressure. The sum of all gas pressure values is equal to the total pressure of the mixture. The pressure of each gas component in the gas mixture is called as partial pressure of that gas. The Dalton law of partial pressure of gas can be written as:

${\text{P}}_{\text{total}}{\text{= P}}_{\text{1}}{\text{+ P}}_{\text{2}}{\text{+ P}}_{\text{3}}\text{…}\text{.}$

Answer to Problem 12SSC

${\text{P}}_{\text{B}}\text{= 0}\text{.45 atm}$

Explanation of Solution

Given information :

Partial pressures of gas A = 0.75 atm

Total pressure = 1.20 atm

Partial pressures of gas A = 0.75 atm

Total pressure = 1.20 atm

Substitute of the values to calculate the partial pressure of gas A:

$\begin{array}{l}{\text{P}}_{\text{total}}{\text{= P}}_{\text{A}}{\text{+ P}}_{\text{B}}\\ \text{1}\text{.20 atm = 0}{\text{.75 atm + P}}_{\text{B}}\\ {\text{P}}_{\text{B}}\text{= 1}\text{.20 - 0}\text{.75 = 0}\text{.45 atm}\end{array}$

Conclusion

${\text{P}}_{\text{B}}\text{= 0}\text{.45 atm}$