Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11, Problem 11.6P
To determine
The largest internal crack in the part.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
I need the answer as soon as possible
The steel has yield strength of 550 MPa and a fracture toughness of 40 MPa m^1/2.What will be the limiting design stress if the maximum tolerable crack is 3.0 mm in length and no plastic deformation is permitted?
A nondestructive testing program for a component made of 1040 steel can ensure that no flaws greater than 1 mm will exist. Will this inspection program be effective in preventing fast fracture?
The steel of interest has a fracture toughness of Klc =120 MPa √m, a tensile modulus of E=207 GPa, a yield strength = 290 MPa, and an ultimate tensile strength of 520 MPa.
Chapter 11 Solutions
Materials Science And Engineering Properties
Ch. 11 - Prob. 1CQCh. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - Prob. 5CQCh. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQ
Ch. 11 - Prob. 11CQCh. 11 - Prob. 12CQCh. 11 - Prob. 13CQCh. 11 - Prob. 14CQCh. 11 - Prob. 15CQCh. 11 - Prob. 16CQCh. 11 - Prob. 17CQCh. 11 - Prob. 18CQCh. 11 - Prob. 19CQCh. 11 - Prob. 20CQCh. 11 - Prob. 21CQCh. 11 - Prob. 22CQCh. 11 - Prob. 23CQCh. 11 - Prob. 24CQCh. 11 - Prob. 25CQCh. 11 - Prob. 26CQCh. 11 - Prob. 27CQCh. 11 - Prob. 28CQCh. 11 - Prob. 29CQCh. 11 - Prob. 30CQCh. 11 - Prob. 1ETSQCh. 11 - Prob. 2ETSQCh. 11 - Prob. 3ETSQCh. 11 - Prob. 4ETSQCh. 11 - Prob. 5ETSQCh. 11 - Prob. 6ETSQCh. 11 - Prob. 7ETSQCh. 11 - Prob. 8ETSQCh. 11 - Prob. 9ETSQCh. 11 - Prob. 10ETSQCh. 11 - Prob. 11.1PCh. 11 - Prob. 11.2PCh. 11 - Prob. 11.3PCh. 11 - Prob. 11.4PCh. 11 - Prob. 11.5PCh. 11 - Prob. 11.6PCh. 11 - Prob. 11.7PCh. 11 - Prob. 11.8PCh. 11 - Prob. 11.9PCh. 11 - Prob. 11.10PCh. 11 - Prob. 11.11PCh. 11 - Prob. 11.12PCh. 11 - Prob. 11.13PCh. 11 - Prob. 11.14P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- The frame of a space shuttle type vehicle must have a high yield strength and high stillness, and the most important design factor is weight. Of all the materials presented in this chapter, what material might be the most suitable for the frame of a space shuttle? Assume that there will be both tensile and compressive stresses. For a space shuttle, cost is not a limiting factor. (a) You can eliminate entire classes of materials from consideration with a brief statement about their unsuitability. (b) What material has the highest specific yield strength? Give the yield strength, specific gravity, specific yield strength, elastic modulus, and specific elastic modulus for this material. (c) What material has the highest specific elastic modulus? Give the yield strength, specific gravity, specific yield strength, elastic modulus, and specific elastic modulus for this material. (d) Compare the materials with the highest specific yield strength and highest specific elastic modulus for suitability in the space shuttle frame. (C) Discuss the suitability of the top-rated material for this design from the viewpoint of the ability to produce a frame.arrow_forwardTask (3) you are asked to perform tensile test on specimens of two different materials (A and B) and you obtained the stress-strain diagram of the two specimens as shown in Figure 2: 400 350 300 250 Material A 200 150 100 50 0.02 0.04 0.06 0.08 0.1 0.12 0.14 0.16 0.18 Strain (mm/mm) 50 Material B 30 20 10 0.02 0.04 0.06 0.08 0.1 Strain (mm/mm) Figure 2: Tensile Test Analysis Stress (MPa) Stress (MPa)arrow_forward(a) the modulus of elasticity in GPa for the Aluminum B) the proportional limit in MPa for the Aluminum C) the ultimate strength in MPa for the Aluminum D) Ductility of material based on percent elongationarrow_forward
- Q3: A cylindrical specimen of steel having an original diameter of (12.8mm) is tensile tested to fracture and found to have engineering fracture strength of (450MP ). If its cross-sectional diameter at fracture is (10.7mm), determine: (1) the ductility in terms of percent reduction in area and (2) the true stress at fracture.arrow_forwardA 7075-T651 alloy is used in a structural component in an airplane. The component must not fail when subjected to a stress of 250 MPa. Several surface flaws have been detected on the component. What is the largest (deepest) surface flaw that could be permitted with the 250 MPa maximum stress? Use data from Table 1 and assume this component geometry and loading condition result in a Y value of 1.25. Yield Strength KI Material MPa ksi MPa√m ksiVin. Metals Aluminum alloy (7075-T651) 495 72 24 22arrow_forwardWhat are the two major considerations for avoiding brittle fracture in ceramics?arrow_forward
- A steel specimen is tested in tension. The specimen is 1" wide by 0.5" thick in the test region. By monitoring the stresses from the testing machine, it was found that the specimen yielded at a stress of 72 ksi and fractured at 96 ksi. (a). Determine the tensile loads at yield and at fracturearrow_forwardi need quickly please please please Which of these cast iron would allow the greatest amount of plastic deformation before fracture . Nodular cast iron Grey cast iron White cast iron None of them can be worked. If the diameter of steel specimen stretched by tension load is doubled , then it’s tensile strength will be Halved Remain unaffected Doubled Become four times Temperature is proportional with Percent of elongation Tensile strength Modulus of elasticity All above The tensile strength of a steel specimen that have a 182 HB , equals to 490 MPa 910 MPa 627 MPa Not given…arrow_forwardA structural component in the shape of a flat plate 24.3 mm thick is to be fabricated from a metal alloy for which the yield strength and plane strain fracture toughness values are 533 MPa and 22.0 MPa-m1/2, respectively. For this particular geometry, the value of Y is 1.3. Assuming a design stress of 0.4 times the yield strength, calculate the critical length of a surface flaw. What formulas do i use ? And how do i use them?arrow_forward
- (b) (i) A tensile test specimen made from 0.4% C steel has a circular cross section of diameter d mm and a gauge length of 25 mm. When a load of 4500 N is applied during the test, the gauge length of the specimen extends to 25.02 mm. If the Young's Modulus of the steel is 199 GPa, calculate the diameter of the tensile test specimen used. 4arrow_forwardA batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250 MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo = 70 MPa and k = 0.74.arrow_forwardI need the answer as soon as possiblearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning