Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 11, Problem 11.1P
To determine
The comparison for the defect lengths in two alumina materials.
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A ceramic part is used under a complete reverse cyclic stress with a stress amplitude (S) of 250 MPa. The yield strength and fracture toughness of materials is 550 MPa and 12.5 MPa*sqrt(m), respectively. Y is 1.4. What is the critical surface crack length?
6)
2- What is the largest size (mm) internal through crack that a thick plate of aluminium alloy
7075-T651 can support at an applied stress of (a) three-quarters of the yield strength and (b)
one-half of the yield strength? Assume Y = 1.
for 7075-T651, KỊC = 24.2 MPa ym and oYS = 495 MPa.
Chapter 11 Solutions
Materials Science And Engineering Properties
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- A thin plate of a ceramic material with E = 225 GPa is loaded in tension, developing a stress of 450 MPa. Is the specimen likely to fail if the most severe flaw present is an internal crack oriented perpendicular to the load axis that has a total length 0.25 mm and a crack tip radius of curvature equal to 1 μm?arrow_forwardIn an engineering application, the material is a strip of iron with a fixed crystallographic structure subject to a tensile load during operation. The part failed (yielded) during operation and needs to be replaced with a component with better properties. You are told that two other iron strips had failed at yield stresses of 110 and 120 MPa, with grain sizes of 30 microns and 25 microns respectively. The current strip has a grain size of 20 microns. The diameter of the rod is 1 mm and the load applied is 100 N. What is the yield stress of the new part C and would you recommend it for operation? Select one: Oa. 133.5 MPa, yes O b. OC. Od Oe. 120.5 MPa, no 129.5, yes 140.5, no 123.5 MPa, yesarrow_forwardA laminated [0/90/0/90]s graphite/epoxy beam is 1 mm thick, is 20 mm wide, and has 0.125 mm thick plies. The lamina properties are E1 = 180 GPa, E2 = 10 GPa, ν12 = 0.28, G12 = 7 GPa Xt = 1700 MPa, Xc = 1400 MPa, Yt = 40 MPa, Yc = 230 MPa (a) Determine the flexural modulus of the beam (b) How could the flexural modulus be improved without changing the ply materials, the number of plies, or the ply orientations? (c) Using the Maximum Stress Criterion for each ply, determine the magnitude of the maximum allowable bending moment that the beam can withstand. Which ply fails first?arrow_forward
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- Q7> Ductile-to-brittle transition temperature (DBTT) is a very important parameter in the design of metallic materials for engineering applications. It has been well known that most of BCC and HCP metals show the DBT phenomenon; however, there is no DBTT in FCC metals. (a) Explain the reason in terms of deformation and fracture. You must compare the BCC and FCC. (b) The ductile fracture surface consists of many dimples. Explain their formation mechanism from the concept of point defects. (c) There are two types in the brittle fracture. Explain and Compare them.arrow_forwardAn aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 34 MPaym. It has been determined that fracture results at a stress of 221 MPa when the maximum (or critical) internal crack length is 2.94 mm. a) Determine the value of Yona for this same component and alloy at a stress level of 287 MPa when the maximum internal crack length is 1.47 mm. MPaymarrow_forward2. The Goodman diagram relates oa and om for fatigue failure after a specific number of cycles Nf, where da is the cyclic stress amplitude, and om the mean stress. For a steel specimen it is found that oa oa (0). [1- (om/OTS)] where Ors is the metal's tensile stress (375MPa), and oa (0)~0.450TS is the 107 cycle fatigue limit at zero mean stress. Assuming the specimen is cycled repeatedly between 0 stress and a peak stress, what is the maximum peak stress if failure in < 107 cycles is to be avoided? Ans: 233 MPaarrow_forward
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