Chapter 10.3, Problem 37PP

Interpretation Introduction

Interpretation:

The mass of $\text{3}\text{.25}$ mol of ${\text{H}}_2{\text{SO}}_4$ needs to be determined.

Concept introduction:

The number of moles can be used to calculate mass of a substance using its molar mass. The relation is represented as follows:

$\begin{array}{l}n=\frac{m}{M}\\ Or,\\ m=n\times M\end{array}$

Here, n is number of moles, m is mass and M is molar mass.

Answer to Problem 37PP

The mass of $\text{3}\text{.25}$ mol of ${\text{H}}_2{\text{SO}}_4$ is 3.18.5 g.

Explanation of Solution

Given Information:

The number of moles of ${\text{H}}_2{\text{SO}}_4$ is 3.25 mol.

Calculation:

To calculate the mass, first calculate molar mass of ${\text{H}}_2{\text{SO}}_4$.

From the above formula, there are 2 H atoms, 1 S atom and 4 O atoms in 1 molecule of ${\text{H}}_2{\text{SO}}_4$.

The molar mass of H, S and O atom is 1 g/mol, 32 g/mol and 16 g/mol respectively. Therefore, molar mass of ${\text{H}}_2{\text{SO}}_4$ will be:

${\text{M}}_{{\text{H}}_2{\text{SO}}_4}=2\left(1\text{ g/mol}\right)+32\text{ g/mol+4}\left(16\text{ g/mol}\right)=98\text{ g/mol}$

Mass of ${\text{H}}_2{\text{SO}}_4$ can be calculated as follows:

$m=n\times M$

Putting the values,

$\begin{array}{l}m=\left(3.25\text{ mol}\right)\left(98\text{ g/mol}\right)\\ =318.5\text{ g}\end{array}$

Conclusion

Therefore, mass of ${\text{H}}_2{\text{SO}}_4$ is $318.5\text{ g}$.