Chapter 10.3, Problem 35PP

Interpretation Introduction

(a)

Interpretation:

The molar mass of ${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH}$ needs to be determined.

Concept introduction:

A molecule is composed of more than type of atoms of different elements. On the basis of bonding with atoms, they can be ionic and covalent compounds. The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Answer to Problem 35PP

${\text{Molar mass of C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH= 45}\text{.99 g/mol}$

Explanation of Solution

Given compound = ${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH}$

Molar mass of C = 12.0 g/mol

Molar mass of O = 15.99 g/mol

Molar mass of H = 1.0 g/mol

Calculate the molar mass of ${\text{C}}_{\text{2}}{\text{H}}_{\text{5}}\text{OH}$ = $\left(\text{2×12}\text{.0}\right)\text{+}\left(\text{1× 15}\text{.99}\right)\text{+}\left(\text{6× 1}\text{.0}\right)\text{ = 45}\text{.99 g/mol}$

Interpretation Introduction

(b)

Interpretation:

The molar mass of $\text{HCN}$ needs to be determined.

Concept introduction:

A molecule is composed of more than type of atoms of different elements. On the basis of bonding with atoms, they can be ionic and covalent compounds. The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Answer to Problem 35PP

$\text{Molar mass of HCN = 27}\text{.0 g/mol}$

Explanation of Solution

Given compound = $\text{HCN}$

Molar mass of C = 12.0 g/mol

Molar mass of N = 14.0 g/mol

Molar mass of H = 1.0 g/mol

Calculate the molar mass of $\text{HCN}$ = $\left(\text{1×12}\text{.0}\right)\text{+}\left(\text{1× 14}\text{.0}\right)\text{+}\left(\text{1× 1}\text{.0}\right)\text{ = 27}\text{.0 g/mol}$

Interpretation Introduction

(c)

Interpretation:

The molar mass of ${\text{CCl}}_{\text{4}}$ needs to be determined.

Concept introduction:

A molecule is composed of more than type of atoms of different elements. On the basis of bonding with atoms, they can be ionic and covalent compounds. The molecular mass of compound is the sum of atomic mass of all the atoms present in the given chemical compound.

Answer to Problem 35PP

${\text{Molar mass of CCl}}_{\text{4}}\text{ = 154 g/mol}$

Explanation of Solution

Given compound = ${\text{CCl}}_{\text{4}}$

Molar mass of C = 12.0 g/mol

Molar mass of Cl = 35.5 g/mol

Calculate the molar mass of ${\text{CCl}}_{\text{4}}$ = $\left(\text{1×12}\text{.0}\right)\text{+}\left(\text{4× 35}\text{.5 }\right)\text{ = 154 g/mol}$