Chapter 10.1, Problem 6PP

a.

Interpretation Introduction

Interpretation:

The representative particle for carbon dioxide needs to be identified and number of moles needs to be determined.

Concept introduction:

In 1 mol of any substance, there are $6.022\times {10}^{23}$ units of that substance. These units can be atoms and molecules. The number of units in 1 mol of any substance is known as Avogadro’s number. It is denoted by symbol N_A.

Answer to Problem 6PP

$\text{6}{\text{.23 mol of CO}}_{\text{2}}$

Explanation of Solution

The given formula is CO₂ which represents a compound. Thus, the representative particle will be molecules. The given number of molecules of carbon dioxide is $3.75\times {10}^{24}$.

The number of moles can be calculated using the following formula:

$n=\frac{N}{N_A}$

Putting the values,

$n=\frac{3.75\times {10}^{24}\text{ molecules}}{6.022\times {10}^{23}\text{ molecules/mol}}=6.23\text{ mol}$

Thus, number of moles of carbon dioxide is 6.23 mol.

b.

Interpretation Introduction

Interpretation:

The representative particle for zinc chloride needs to be identified and number of moles needs to be determined.

Concept introduction:

In 1 mol of any substance, there are $6.022\times {10}^{23}$ units of that substance. These units can be atoms and molecules. The number of units in 1 mol of any substance is known as Avogadro’s number. It is denoted by symbol N_A.

Answer to Problem 6PP

$\text{0}{\text{.6 mol of ZnCl}}_{\text{2}}$.

Explanation of Solution

The given formula is ${\text{ZnCl}}_{\text{2}}$ which represents a compound. Thus, the representative particle will be molecules. The given number of molecules of zinc chloride is $3.58\times {10}^{23}$.

The number of moles can be calculated using the following formula:

$n=\frac{N}{N_A}$

Putting the values,

$n=\frac{3.58\times {10}^{23}\text{ molecules}}{6.022\times {10}^{23}\text{ molecules/mol}}=0.6\text{ mol}$

Thus, number of moles of zinc chloride is 0.6 mol.