Chapter 10.2, Problem 17PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of Ag needs to be determined.

Concept introduction:

Number of moles in the ratio of weight to its gram molecular weight of the respective element.

Answer to Problem 17PP

Number of moles in $25\cdot 5\text{ g}$ of $\text{Ag = 0}\cdot 2364$.

Explanation of Solution

Given information:

Weight of $\text{Ag = }25\cdot 5\text{ g}$

Formula used:

$\text{Number of moles = }\frac{\text{Weight}}{\text{gram molecular weight}}$

Calculation:

Given weight of $\text{Ag = }25\cdot 5\text{ g}$

Gram molecular weight of $\text{Ag}=107\cdot 89$

Substitute these in the above formula

$\text{moles = }\frac{\text{Weight}}{\text{gram molecular weight}}$

$\text{Number of moles = }\frac{25\cdot 5}{107\cdot 89}=0\cdot 2364$

Interpretation Introduction

(b)

Interpretation:

The number of moles of S needs to be determined.

Concept introduction:

Number of moles in the ratio of weight to gram molecular weight of respective element.

Answer to Problem 17PP

The number of moles of S is $9\cdot 375$ mol.

Explanation of Solution

Given information Weight of $S=300\text{ g}$

Formula used:

$\text{Number of moles = }\frac{\text{Weight}}{\text{gram molecular weight}}$

Calculation:

Given weight of $S=300\text{ g}$

Gram molecular weight of $S=32\text{ g/mol}$

Substitute in the above formula

$\text{moles = }\frac{\text{Weight}}{\text{gram molecular weight}}$

$\text{Number of moles = }\frac{300\text{ g}}{32\text{ g/mol}}=9\cdot 375\text{ mol}$