Chapter 10, Problem 133A

Interpretation Introduction

(a)

Interpretation:

The number of moles should be calculated present in 100.0 g of dinitrogen oxide.

Concept introduction:

Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number i.e. $6.022\times {10}^{23}$ atoms.

Answer to Problem 133A

Number of moles of dinitrogen oxide = $\text{2}\text{.27 g/mole}$

Explanation of Solution

Mass of dinitrogen oxide = 100.0 g

Molar mass of dinitrogen oxide = 44.013 g/mole

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

Number of moles of dinitrogen oxide = $\frac{\text{100}\text{.0 g}}{\text{44}\text{.013 g/mole}}$

Number of moles of dinitrogen oxide = $\text{2}\text{.27 g/mole}$

Interpretation Introduction

(b)

Interpretation:

The number of moles should be calculated present in 100.0 g of methanol ( ${\text{CH}}_{\text{3}}\text{OH}$ ).

Concept introduction:

Number of moles of a compound is defined as the ratio of given mass of the compound to the molar or molecular mass of the compound.

The mathematical expression is given by:

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

The one mole of any substance is equal to the Avogadro number i.e. $6.022\times {10}^{23}$ atoms.

Answer to Problem 133A

Number of moles of methanol = $\text{3}\text{.12 g/mole}$

Explanation of Solution

Mass of methanol = 100.0 g

Molar mass of methanol = 32.04 g/mole

Number of moles = $\frac{\text{mass of the compound}}{\text{molar mass of the compound}}$

Number of moles of methanol = $\frac{\text{100}\text{.0 g}}{\text{32}\text{.04 g/mole}}$

Number of moles of methanol = $\text{3}\text{.12 g/mole}$