Chapter 10.3, Problem 32PP

Interpretation Introduction

Interpretation:

The number of moles of oxygen atoms present in $5.00$ mol of diphosphorus pentoxide $\left(P_2{O}_5\right).$ needs to be determined.

Concept introduction:

Mole concept to be used here,

$1$ mol of substance contains $6.023\times {10}^{23}$ particles/atoms/molecules.

$1\text{ mole }=\frac{\text{given mass}}{\text{molar mass/atomic/molecular mass}}$

$1$ mole also be expressed in terms of volume of volume of substance.

Answer to Problem 32PP

$1.15\times {10}^1$ moles of oxygen atoms.

Explanation of Solution

When $1$ mole of a substance breaks into its constituent atoms it generates efficient number of atoms.

When $1$ mole of $AxBy$ breaks or dissociates it gives,

$AxBy\to x\text{ moles of }A+y\text{ moles of }B.$

When $n$ moles of $AxBy$ breaks, it given,

$\eta AxBy\to \eta x\text{ moles of }A+\eta y\text{ moles of }B$

Calculation:

$1$ mol of $\left(P_2{O}_5\right)\to 5$ moles of oxygen atom.

$5$ Mole of $P_2{O}_5$ will gives $\to 5\times 5$ moles of oxygen atoms.

$\to 25$ Moles of oxygen atoms.

Conclusion

$5$ moles of diphosphorus pentoxide gives $25$ moles of oxygen atom.