Chapter 10, Problem 13STP

Interpretation Introduction

Interpretation:

The number of chlorine atoms required to make 18 iron(III) chloride particles should be determined.

Concept introduction:

The ratio of amount of any two atoms involved in a compound in terms of number of atoms is said to be ratio of atoms in the compound which is fixed ratio for a compound.

Answer to Problem 13STP

The number of chlorine atoms required to make 18 iron(III) chloride particles is (d) $54\text{ Cl atoms}$.

Explanation of Solution

The given compound is iron(III) chloride, for which 2 iron atoms combine with 6 chlorine atoms to form 2 particles of iron(III) chloride. So, the ratio of number of atoms of iron and chlorine in iron(III) chloride is 1:3 and the ratio of number of chlorine atoms to iron(III) chloride is 3:1. Thus, the number of chlorine atoms required to make 18 iron(III) chloride particles will be:

$\text{18 iron}\left(\text{III}\right)\text{ chloride particles }\times \frac{3\text{ chlorine atoms}}{\text{1 iron}\left(\text{III}\right)\text{ chloride particle}}\text{ = 54 chlorine atoms }$

Hence, the number of chlorine atoms required to make 18 iron(III) chloride particles is $54$.