Chapter 10.3, Problem 53SSC

Interpretation Introduction

Interpretation:

The base graph representing the number of moles of each element needs to be designed.

Concept introduction:

Number of moles in the ratio of mass to molar mass of a compound.

Explanation of Solution

Given information:

Mass of compound $=500\text{ g}$

Molecular formula of compound:

${\text{=C}}_{\text{12}}{\text{H}}_{\text{4}}{\text{Cl}}_{\text{4}}{\text{O}}_{\text{2}}\left(\text{molar mass = 323 g/mol}\right)$

Using the formula

$\text{number of moles =}\frac{\text{mass}}{\text{molar mass}}$

Find out the total number of moles as follows:

$\begin{array}{l}\text{Total moles = }\\ =\frac{500}{12\times 12+4\times 1+4\times 35\cdot 5+2\times 16}\\ =\frac{500}{322}\\ =1\cdot 5527\end{array}$

Using this find individual moles of each element

$\begin{array}{l}12\text{ carbons = 12}\times 1\cdot 5527=18\cdot 6\text{ moles of C}\\ 4\text{ Hydrogen = 4}\times 1\cdot 5527=6\cdot 2\text{ moles of H}\\ \text{4 Chlorine = 4}\times 1\cdot 5527=6\cdot 2\text{ moles of Cl}\\ \text{2 Oxygen = 2}\times 1\cdot 5527=3\cdot 1\text{ moles of O}\end{array}$

Therefore moles of each elements are found using this information plot bar graph as follows:

Step − 1: Access the window to plot graph.

Step − 2: Enter the data in the box provided.

Step − 3: Press the button to plot graph.

Step − 4: The graph obtained is as follow:

Conclusion

The graph represents number of moles of each element in the compound as follows:

$\begin{array}{l}\text{C}-18\cdot 6\text{ moles}\\ \text{H}-6\cdot 2\text{ moles}\\ \text{Cl}-6\cdot 2\text{ moles}\\ \text{O}-3\cdot 1\text{ moles}\end{array}$