Biochemistry: The Molecular Basis of Life
6th Edition
ISBN: 9780190209896
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 10, Problem 17RQ
Summary Introduction
To review:
The comparison between the energy from one mole of glucose captured in glycolysis and in oxidative phosphorylation.
Introduction:
Glycolysis, as the term suggests, is the breakdown of a glucose molecule into two pyruvate molecules. This process occurs sequentially in steps and is catalyzed by different enzymes. Oxidative phosphorylation is a process that ends in the production of ATP by the oxidation of electron carriers. Glycolysis is a process that takes place inside the cytoplasm of the cell, while oxidative phosphorylation takes place in the mitochondria.
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The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism
of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.
Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
Chapter 10 Solutions
Biochemistry: The Molecular Basis of Life
Ch. 10 - Prob. 1QCh. 10 - Prob. 2QCh. 10 - Prob. 3QCh. 10 - Prob. 4QCh. 10 - Prob. 5QCh. 10 - Prob. 6QCh. 10 - Prob. 7QCh. 10 - Prob. 8QCh. 10 - Prob. 1RQCh. 10 - Prob. 2RQ
Ch. 10 - Prob. 3RQCh. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQCh. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13RQCh. 10 - Prob. 14RQCh. 10 - Prob. 15RQCh. 10 - Prob. 16RQCh. 10 - Prob. 17RQCh. 10 - Prob. 18RQCh. 10 - Prob. 19RQCh. 10 - Prob. 20RQCh. 10 - Prob. 21RQCh. 10 - Prob. 22RQCh. 10 - Prob. 23RQCh. 10 - Prob. 24RQCh. 10 - Prob. 25RQCh. 10 - Prob. 26RQCh. 10 - Prob. 27RQCh. 10 - Prob. 28RQCh. 10 - Prob. 29RQCh. 10 - Prob. 30RQCh. 10 - Prob. 31RQCh. 10 - Prob. 32RQCh. 10 - Prob. 33RQCh. 10 - Prob. 34RQCh. 10 - Prob. 35FBCh. 10 - Prob. 36FBCh. 10 - Prob. 37FBCh. 10 - Prob. 38FBCh. 10 - Prob. 39FBCh. 10 - Prob. 40FBCh. 10 - Prob. 41FBCh. 10 - Prob. 42FBCh. 10 - Prob. 43FBCh. 10 - Prob. 44FBCh. 10 - Prob. 45SACh. 10 - Prob. 46SACh. 10 - Prob. 47SACh. 10 - Prob. 48SACh. 10 - Prob. 49SACh. 10 - Prob. 50TQCh. 10 - Prob. 51TQCh. 10 - Prob. 52TQCh. 10 - Prob. 53TQCh. 10 - Prob. 54TQCh. 10 - Prob. 55TQCh. 10 - Prob. 56TQCh. 10 - Prob. 57TQCh. 10 - Prob. 60TQCh. 10 - Prob. 61TQCh. 10 - Prob. 62TQCh. 10 - Prob. 63TQCh. 10 - Prob. 64TQCh. 10 - Prob. 65TQCh. 10 - Prob. 66TQ
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