Concept explainers
Interpretation:
The expression for (δp / δV)T, n for a van der Waals gas and for the virial equation in terms of volume is to be stated.
Concept introduction:
The
Answer to Problem 1.39E
The expression for
Explanation of Solution
The ideal
Vander Waals equation is based on the reasons that non-ideal gases do not obey the ideal gas equation. Notably, the van Waals equation improves the ideal gas law by adding two significant terms in the ideal gas equation: one term is to account for the volume of the gas molecules and another term is introduced for the attractive forces between them. The non-ideal gas equation represented as;
In the above equation,
‘a’ and ‘b’ are called as van der Waals constants and ‘a’ represents the pressure correction and it is related to the magnitude and strength of the interactions between gas particles. Similarly, ‘b’ describes the volume correction and it is having relationship to the size of the gas particles. When the value of V is large and ‘n’ is comparatively small, both corrections become negligible. Thus, the van der Waals equation contracts to the ideal gas equation PV = nRT. Such situations are for a gas having relatively lower number of gas molecules, occupying in a relatively larger volume i.e., the gas is at lower pressure. Generally, at low pressures, the correction term ‘a’ is more predominant than the correction term for volume ‘b’. At high pressures, the correction term for the volume of the gas molecules is predominant since, the molecules are incompressible and occupies a notable fraction of the total volume of gas.
On taking the derivative of this expression with respect to temperature, we can get the expression for
Both the term in the above expression has a volume as a variable so the derivative of pressure with respect to volume will give two terms. Thus,
Thus, variation of pressure with respect to temperature having the volume ‘V’ with them. Varying the quantities of volume will result in the variation of
The expression for
Want to see more full solutions like this?
Chapter 1 Solutions
Physical Chemistry
- What properties of a nonideal gas do the Vander Waals constants represent?arrow_forwardUnder what conditions would the van der Waals constant b be negative? Do you think there are any gases for which this occurs?arrow_forwardUse the approximation 1 x-1 1 x x2 to determine an expression for the virial coefficient C in terms of the van der Waals constants.arrow_forward
- Under what conditions does the behavior of a real gas begin to differ significantly from the ideal gas law?arrow_forwardAt the critical point for carbon dioxide, the substance is very far from being an ideal gas. Prove this statement by calculating the density of an ideal gas in g/cm3 at the conditions of the critical point and comparing it with the experimental value. Compute the experimental value from the fact that a mole of CO2 at its critical point occupies 94 cm3.arrow_forwardWhat is the van der Waals constant a for Ne in units of bar.cm6/mol2arrow_forward
- Scottish physicist W. J. M. Rankine proposed an absolute temperature scale based on the Fahrenheit degree, now called degree Rankine abbreviated R and used by some engineering fields. If a degree Rankine is 5/9 of a degree Kelvin, what is the value of the ideal gas law constant in L. atm/mol. R?arrow_forwardAt high temperatures, one of the van der Waals constants can be ignored. Which one? Justify your choice and write a high temperature version of the van der Waals equation of state.arrow_forwardNumerically evaluate for one mole of methane acting as a van der Waals gas at a T = 298 K and V = 25.0 L and b T = 1000 K and V = 250.0 L. Comment on which set of conditions yields a number closer to that predicted by the ideal gas law. pVT,narrow_forward
- Referring to exercises 1.6 and 1.7, does it matter if the pressure difference is caused by an ideal gas or a non-ideal gas? Explain your answer.arrow_forward2. The species identified with each curve in the Maxwell-Boltzmann plot below are: (Assume all gases are at the same temperature.) A = Xe, B = O2, C = Ne, and D = He A = Xe, B = He. C = Ne, and D = O2 A = He, B = Ne, C = O2, and D = Xe A = He, B = O2, C = Ne, and D = Xe Molecular speed (m/s)arrow_forwardA sample of a smoke stack emission was collected into a 1.25-L tank at 752 mm Hg and analyzed. The analysis showed 92% CO2, 3.6% NO, 1.2% SO2, and 4.1% H2O by mass. What is the partial pressure exerted by each gas?arrow_forward
- Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning