12 1. (2 pt) Draw the Haworth projections of the a-furanose and pyranose forms of the sugar shown below. Pay close attention to D-/L- and the correct anomeric carbon for the furanose. H-C-Olt 15 CH₂Olt +10 diasterio mer=2+
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- where is a reducing end in this image? I initially thought it'd be on the middle oxygen connecting the lactose molecules since it's the only reducing sugar, but that was incorrect for some reason.1. Draw the structure of the L-isomer of the Fisher projection of one epimer of D-allopyronoside. Discuss why is this an epimer of the monosaccharide. 2. Is this saccharide a good substrate for glycolysis? Explain.Use the two Fischer projections shown below to draw the Haworth projection of these two sugars linked by an a(1-2) linkage, with the ß isoform of the ketohexose. H H ㅎ HO H H OH OH ОН Н НО CH₂OH 애,애애 OH CH₂OH OH H OH OH OH I OH CH₂OH OH OH OH Eng са CH2OH CH2OH OH OH ОН ОН CH₂OH Н OH Н Н OH Н T I CH₂OH CH₂OH OH OH OH CH₂OH CH₂OH Н CH₂OH CH₂OH ОН OH OH НО OH H Н OH CH₂OH
- Draw the products formed when -D-idose is treated with C6H5NHNH2 (excess), H+A novel sugar "D-Lasallose' was isolated from a native edible mountain mushroom by a group of DLSU-D Biochemistry researchers under Sir Gids. Given the Fischer projection structure of D-Lasallose below,show the systematic conversion into the equivalent Haworth structures and give the systematic names of both anomers.Consider the Haworth projections of f-L-galactose and B-L-glucose shown here. ОН CH OH ОН ОН B-L-galactose enantiomers anomers OH diastereomers epimers ОН CH₂OH OH Which terms describe the relationship between these two sugars? ОН OH B-L-glucose
- Draw the enediolate intermediate of the ribulose-5-phosphate isomerasereaction (Ru5P → R5P).Gentiobiose has the molecular formula C12H22O11 and has been isolated from gentian root and by hydrolysis of amygdalin. Gentiobiose exists in two different forms, one melting at 86°C and the other at 190°C. The lower melting form is dextrorotatory ([α] 16°), the higher melting one is levorotatory ([α] -6°). The rotation of an aqueous solution of either form, however, gradually changes until a final value of [α] 9.6° is observed. Hydrolysis of gentiobiose is efficiently catalyzed by emulsin and produces two moles of D-glucose per mole of gentiobiose. Gentiobiose forms an octamethylether, which on hydrolysis in dilute acid yields 2,3,4,6-tetra-O-methyl-D-glucose and 2,3,4-tri-O-methyl-D-glucose. What is the structure of gentiobiose? EXPLAIN IN DETAIL.The amount of branching (number of (α1→6) glycosidic bonds) in amylopectin can be determined by the following procedure. A sample of amylopectin is exhaustively methylated—treated with a methylating agent (methyl iodide) that replaces the hydrogen of every sugar hydroxyl witha methyl group, converting —OH to —OCH3 . All the glycosidic bonds in the treated sample are then hydrolyzed in aqueous acid, and the amount of 2,3-di-O-methylglucose so formed is determined.(a) Explain the basis of this procedure for determining the number of (α1→6) branch points in amylopectin. What happens to the unbranched glucose residues in amylopectin during the methylation and hydrolysis procedure?(b) A 258 mg sample of amylopectin treated as described above yielded 12.4 mg of 2,3-di-O-methylglucose. Determine what percentage of the glucose residues in the amylopectin contained an (α1→6) branch. (Assume that the average molecular weight of a glucose residue in amylopectin is 162 g/mol.)