A certain chemical reaction releases 134. kJ of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put into a calorimeter (a device for measuring heat flow). It takes 3.11 J of heat energy to raise the temperature of this calorimeter by 1 °C. Now the reaction is run until all the reactant is gone, and the temperature of the calorimeter is found to rise by 9.7 °C. How would you calculate the number of moles of reactant that were consumed? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. moles consumed = ولا 0x10 DO 0
A certain chemical reaction releases 134. kJ of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put into a calorimeter (a device for measuring heat flow). It takes 3.11 J of heat energy to raise the temperature of this calorimeter by 1 °C. Now the reaction is run until all the reactant is gone, and the temperature of the calorimeter is found to rise by 9.7 °C. How would you calculate the number of moles of reactant that were consumed? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. moles consumed = ولا 0x10 DO 0
Chapter11: Health Of Aquatic Animals
Section: Chapter Questions
Problem 3KA
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Transcribed Image Text:A certain chemical reaction releases 134. kJ of heat energy per mole of reactant consumed. Suppose some moles of the reactant are put into a calorimeter (a
device for measuring heat flow). It takes 3.11 J of heat energy to raise the temperature of this calorimeter by 1 °C. Now the reaction is run until all the reactant
is gone, and the temperature of the calorimeter is found to rise by 9.7 °C. How would you calculate the number of moles of reactant that were consumed?
Set the math up. But don't do any of it. Just leave your answer as a math expression.
Also, be sure your answer includes all the correct unit symbols.
moles consumed =
ولا
0x10
DO
0
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