1. (4.1) One of the alkenes is nonpolar and the other is polar. Which is which? Explain your answer. F F H F H H F H

Give a clear handwritten answer with explanation...

Give the IUPAC name for each aldehyde.

2-butanol can be formed as the only product of the Markovnikov addition of H2O to two different alkenes. In contrast, 2-nonanol can be formed as the only product of the Markovnikov addition of H2O to just one alkene. To examine the difference, draw the alkene starting materials of each alcohol. Part 1 of 2 Draw the bond-line (skeletal) structures of the two alkene starting materials that can be used to synthesize 2-butanol via Markovnikov hydration. Click and drag to start drawing a structure. 0* Part 2 of 2 Draw the bond-line (skeletal) structure of the alkene starting material that can be used to synthesize 2-nonanol selectively via Markovnikov hydration. Click and drag to start drawing a structure.

H OH CH2OH D H ОН H الحزن ОН CH2OH ОН H ОН I Which of the following statements correctly describes this structure? (A) The monomer units are bonded by beta 1-2 glycosidic linkage. B The monomer units are bonded by alpha 1-2 glycosidic linkage. The monomer units are bonded by alpha 1-4 glycosidic linkage. The monomer units are bonded by beta 1-4 glycosidic linkage. H CH2OH H ОН H ОН H ОН

The reaction of methoxy benzene with hydrogen iodide will yield a phenol and an alkyl halide. Which of following choices is the correct combination of the products?

1-39. Classify each of the molecules in problem 1-37 as D-enantiomer or an L-enantiomer

Column A shows the names of some of the c functional groups. Column B shows their structure. Match each entry in column A one in column B.

In the monosaccharide derivatives known as sugar alcohols, the carbonyl oxygen is reduced to a hydroxyl group. For example, D-glyceraldehyde can be reduced to glycerol. However, this sugar alcohol is no longer designated D or L. Why?

Thiamin, or Vitamin B1, contains a positively chargedfive-membered ring called a thiazolium ring. Explainwhy the thiazolium ring is aromatic.