Chapter 6.4, Problem 2QR

To determine

To find $dy/dx$ .

Answer to Problem 2QR

  $\frac{dy}{dx}=\sin 2x$

Explanation of Solution

Given: Function is

  $y={\left(\sin x\right)}^2$

Calculation:

  $y={\left(\sin x\right)}^2$

Differentiate with respect to $x$

  $\begin{array}{l}\frac{dy}{dx}=\frac{d}{dx}\left({\left(\sin x\right)}^2\right)\\ =2\sin x\frac{d}{dx}\left(\sin x\right)\\ =2\sin x\cos x\\ =\sin 2x\end{array}$