Chapter 6.1, Problem 3QR

To determine

To find: the velocity after 10 seconds and answers in ft/sec and then change it to mi/h.

Answer to Problem 3QR

100 $\text{ft}/{\sec }^2$

68.18 mph

Explanation of Solution

Given:

Acceleration = 10 $\text{ft}/{\sec }^2$

Time = 10 seconds

Formula used:

  $\upsilon =\text{ Acceleration}\times T\text{ime }$

Calculation:

  $\begin{array}{c}\upsilon =\text{ Acceleration}\times T\text{ime }\\ \text{=10 }\text{ft}/{\sec }^2\times 10\sec \\ =100\text{ft}/\text{sec}\end{array}$

Convert to mph:

  $\begin{array}{l}=\frac{100\text{ft}}{1\text{ sec}}\times \frac{1\text{ mi}}{5280\text{ft}}\times \frac{3600\text{sec}}{1\text{h}}\\ =68.18\text{mph}\end{array}$

The velocity after 10 seconds is 100 ft/sec or 68.18 mph.