(a)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(a)
Answer to Problem 98A
So, no. of neutrons is 48.
Explanation of Solution
Given isotope:
The
The mass number is 84.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 48.
(b)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(b)
Answer to Problem 98A
So, no. of neutrons is 44.
Explanation of Solution
Given isotope:
The atomic number is 35. The atomic number is no. of protons.
The mass number is 79.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 44.
(c)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(c)
Answer to Problem 98A
So, no. of neutrons is 114.
Explanation of Solution
Given isotope:
The atomic number is 76. The atomic number is no. of protons.
The mass number is 190.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 114.
(d)
Interpretation: To determine the number of isotopes in an isotope.
Concept introduction:
Isotopes are any two or more different chemical forms of the same element that have the same number of protons but varying numbers of neutrons in their nucleus.
(d)
Answer to Problem 98A
So, no. of neutrons is 110.
Explanation of Solution
Given isotope:
The atomic number is 75. The atomic number is no. of protons.
The mass number is 185.
Expression for mass number is,
So, calculate no. of neutrons as shown,
So, no. of neutrons is 110.
Chapter 6 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Show work with explanation needed. don't give Ai generated solutionarrow_forwardGive detailed Solution with explanation needed with structures. don't give Ai generated solution. avoid handwritten Solutionarrow_forwardThe acid-base indicator HX undergoes the following reaction in a dilute aqueous solution: HX (color 1) H+ + X- (color 2). The following absorbance data were obtained for a 0.00035 M solution of HX in 0.1 M NaOH and 0.1 M HCI. Measurements were made at wavelengths of 450 nm and 620 nm using a 1.0 cm glass cuvette. 450 620 A(460 nm) A(630 nm) 0.1 M NaOH 0.1 M HCI 0.065 0.435 0.895 0.150 In the 0.1M NaOH solution, the indicator will be almost 100% in the X- form, while in 0.1M HCI, the indicator will be nearly 100% protonated (HX). Calculate the acid dissociation constant for the indicator if a pH=5 buffer solution containing a very small amount of indicator exhibits an absorbance of 0.567 at 450 nm and 0.395 at 620 nm (measured in a 1 cm glass cuvette).arrow_forward
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