Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
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Question
Chapter 6, Problem 53A
Interpretation Introduction
Interpretation:
Which will have higher first ionization enthalpy metals or nonmetals is to be explained.
Concept Introduction :
The first ionization energy is the energy needed for the extraction of the outermost electron from the neutral gaseous atom.
Expert Solution & Answer
Answer to Problem 53A
Non-metals
Explanation of Solution
Metallic character decreases across the period or from left to right in the periodic table. First, ionization energy increases across the period because of a decrease in atomic size. The ionization energy is inversely related to the atomic radius. The higher the atomic radius, the lower will be the ionization energy.
Thus, nonmetals have higher first ionization energy.
Chapter 6 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
Ch. 6.1 - Prob. 1LCCh. 6.1 - Prob. 2LCCh. 6.1 - Prob. 3LCCh. 6.1 - Prob. 4LCCh. 6.1 - Prob. 5LCCh. 6.1 - Prob. 6LCCh. 6.1 - Prob. 7LCCh. 6.1 - Prob. 8LCCh. 6.2 - Prob. 9SPCh. 6.2 - Prob. 10SP
Ch. 6.2 - Prob. 11LCCh. 6.2 - Prob. 12LCCh. 6.2 - Prob. 13LCCh. 6.2 - Prob. 14LCCh. 6.2 - Prob. 15LCCh. 6.2 - Prob. 16LCCh. 6.2 - Prob. 17LCCh. 6.3 - Prob. 18LCCh. 6.3 - Prob. 19LCCh. 6.3 - Prob. 20LCCh. 6.3 - Prob. 21LCCh. 6.3 - Prob. 22LCCh. 6.3 - Prob. 23LCCh. 6.3 - Prob. 24LCCh. 6.3 - Prob. 25LCCh. 6 - Prob. 26ACh. 6 - Prob. 27ACh. 6 - Prob. 28ACh. 6 - Prob. 29ACh. 6 - Prob. 30ACh. 6 - Prob. 31ACh. 6 - Prob. 32ACh. 6 - Prob. 33ACh. 6 - Prob. 34ACh. 6 - Prob. 35ACh. 6 - Prob. 36ACh. 6 - Prob. 37ACh. 6 - Prob. 38ACh. 6 - Prob. 39ACh. 6 - Prob. 40ACh. 6 - Prob. 41ACh. 6 - Prob. 42ACh. 6 - Prob. 43ACh. 6 - Prob. 44ACh. 6 - Prob. 45ACh. 6 - Prob. 46ACh. 6 - Prob. 47ACh. 6 - Prob. 48ACh. 6 - Prob. 49ACh. 6 - Prob. 50ACh. 6 - Prob. 51ACh. 6 - Prob. 52ACh. 6 - Prob. 53ACh. 6 - Prob. 54ACh. 6 - Prob. 55ACh. 6 - Prob. 56ACh. 6 - Prob. 57ACh. 6 - Prob. 58ACh. 6 - Prob. 59ACh. 6 - Prob. 60ACh. 6 - Prob. 61ACh. 6 - Prob. 62ACh. 6 - Prob. 65ACh. 6 - Prob. 66ACh. 6 - Prob. 67ACh. 6 - Prob. 68ACh. 6 - Prob. 69ACh. 6 - Prob. 70ACh. 6 - Prob. 71ACh. 6 - Prob. 72ACh. 6 - Prob. 74ACh. 6 - Prob. 75ACh. 6 - Prob. 76ACh. 6 - Prob. 78ACh. 6 - Prob. 80ACh. 6 - Prob. 81ACh. 6 - Prob. 82ACh. 6 - Prob. 83ACh. 6 - Prob. 85ACh. 6 - Prob. 86ACh. 6 - Prob. 87ACh. 6 - Prob. 88ACh. 6 - Prob. 89ACh. 6 - Prob. 90ACh. 6 - Prob. 91ACh. 6 - Prob. 92ACh. 6 - Prob. 93ACh. 6 - Prob. 94ACh. 6 - Prob. 95ACh. 6 - Prob. 96ACh. 6 - Prob. 97ACh. 6 - Prob. 98ACh. 6 - Prob. 99ACh. 6 - Prob. 100ACh. 6 - Prob. 1STPCh. 6 - Prob. 2STPCh. 6 - Prob. 3STPCh. 6 - Prob. 4STPCh. 6 - Prob. 5STPCh. 6 - Prob. 9STPCh. 6 - Prob. 10STPCh. 6 - Prob. 11STPCh. 6 - Prob. 12STP
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- The acid-base indicator HX undergoes the following reaction in a dilute aqueous solution: HX (color 1) H+ + X- (color 2). The following absorbance data were obtained for a 0.00035 M solution of HX in 0.1 M NaOH and 0.1 M HCI. Measurements were made at wavelengths of 450 nm and 620 nm using a 1.0 cm glass cuvette. 450 620 A(460 nm) A(630 nm) 0.1 M NaOH 0.1 M HCI 0.065 0.435 0.895 0.150 In the 0.1M NaOH solution, the indicator will be almost 100% in the X- form, while in 0.1M HCI, the indicator will be nearly 100% protonated (HX). Calculate the acid dissociation constant for the indicator if a pH=5 buffer solution containing a very small amount of indicator exhibits an absorbance of 0.567 at 450 nm and 0.395 at 620 nm (measured in a 1 cm glass cuvette).arrow_forwardShow work...give the name of the given compound. Don't give Ai generated solutionarrow_forwardShow work with explanation needed. don't give Ai generated solutionarrow_forward
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