(a)
Interpretation: The element having a greater attraction for electrons is to be determined.
Concept introduction:
An atom's tendency to attract the bonding electrons into a covalent bond is known as electronegativity.
(a)
Answer to Problem 47A
O
Explanation of Solution
The electronegativity decreases down the group and increases across the period. Ca is present in group 2 and O is in group 16. So, element O is present on the right side of the periodic table.
Thus, O will have more electronegativity than Ca.
(b)
Interpretation: The element having a greater attraction for electrons is to be determined.
Concept introduction:
An atom's tendency to attract the bonding electrons into a covalent bond is known as electronegativity.
(b)
Answer to Problem 47A
F
Explanation of Solution
The electronegativity decreases down the group and increases across the period. Element O is present in group 16 while F is present in group 17. The electronegativity increases from left to right.
Thus, the electronegativity of F is more than O and it will attract more electrons.
(c)
Interpretation: The element having a greater attraction for electrons is to be determined.
Concept introduction:
An atom's tendency to attract the bonding electrons into a covalent bond is known as electronegativity.
(c)
Answer to Problem 47A
O
Explanation of Solution
The electronegativity decreases down the group and increases across the period. H is present in group 1 which is on the extreme left of the periodic table. Element O is present in group 16 which on the right side of the periodic table
Thus, the electronegativity of O is more than H and it will attract more electrons.
(d)
Interpretation: The element having a greater attraction for electrons is to be determined.
Concept introduction:
An atom's tendency to attract the bonding electrons into a covalent bond is known as electronegativity.
(d)
Answer to Problem 47A
S
Explanation of Solution
The electronegativity decreases down the group and increases across the period. K is present in group 1 which is on the extreme left of the periodic table. Element S is present in group 16 which is on the right side of the periodic table. The electronegativity increases from left to right.
Thus, the electronegativity of S is more than K and it will attract more electrons.
Chapter 6 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- The acid-base indicator HX undergoes the following reaction in a dilute aqueous solution: HX (color 1) H+ + X- (color 2). The following absorbance data were obtained for a 0.00035 M solution of HX in 0.1 M NaOH and 0.1 M HCI. Measurements were made at wavelengths of 450 nm and 620 nm using a 1.0 cm glass cuvette. 450 620 A(460 nm) A(630 nm) 0.1 M NaOH 0.1 M HCI 0.065 0.435 0.895 0.150 In the 0.1M NaOH solution, the indicator will be almost 100% in the X- form, while in 0.1M HCI, the indicator will be nearly 100% protonated (HX). Calculate the acid dissociation constant for the indicator if a pH=5 buffer solution containing a very small amount of indicator exhibits an absorbance of 0.567 at 450 nm and 0.395 at 620 nm (measured in a 1 cm glass cuvette).arrow_forwardShow work...give the name of the given compound. Don't give Ai generated solutionarrow_forwardShow work with explanation needed. don't give Ai generated solutionarrow_forward
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