Chapter 6, Problem 37A

(a)

Interpretation Introduction

Interpretation:To write the electronic configuration of a Nobel gas belonging to period 3.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

Answer to Problem 37A

  $\left[\text{Ne}\right]3s^{2}3p^6$

Explanation of Solution

The Nobel gas belonging to period 3 is Argon. Its atomic number is $18$ . So, its electronic configuration is,

  $\text{Ar}\left(18\right):\left[\text{Ne}\right]3s^{2}3p^6$

(b)

Interpretation Introduction

Interpretation:To write the electronic configuration of a metalloid belonging to period 3.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

Answer to Problem 37A

  $\left[\text{Ne}\right]3s^{2}3p^2$

Explanation of Solution

The metalloid belonging to period 3 is silicon. Its atomic number is $14$ . So, its electronic configuration is,

  $\text{Si}\left(14\right):\left[\text{Ne}\right]3s^{2}3p^2$

(c)

Interpretation Introduction

Interpretation:To write the electronic configuration of an alkaline earth metal belonging to period 3.

Concept introduction:

The electron configuration of an element defines how its electrons are arranged throughout its atomic orbitals. Standard notation is used to represent atomic electron configurations, placing all electron-containing atomic subshells in sequential order. The number of electrons held by the subshell is indicated by superscript.

Answer to Problem 37A

  $\left[\text{Ne}\right]3s^2$

Explanation of Solution

The alkaline earth metal belonging to period 3 is magnesium. Its atomic number is 2. So, its electronic configuration is,

  $\text{Mg}\left(12\right):\left[\text{Ne}\right]3s^2$