Chapter 6, Problem 96A

Interpretation Introduction

Interpretation:

To determine the volume of acetone.

Concept Introduction :

The relation between mass, volume, and density is as shown:

  $\text{density}=\frac{\text{mass}}{\text{volume}}$

Answer to Problem 96A

The density of acetone is $\text{257}\text{.38 mL}$ .

Explanation of Solution

The volume of mercury: $15.0\text{ mL}$

Density of mercury: $13.59\text{g}/\text{mL}$

Density of acetone: $0.792\text{g}/\text{mL}$

First, calculate the mass of mercury

  $\begin{array}{c}\text{density}=\frac{\text{mass}}{\text{volume}}\\ \text{mass}=\text{density}\times \text{volume}\\ =13.59\text{g}/\text{mL}\times 15.0\text{ mL}\\ =\text{203}\text{.85 g}\end{array}$

Now, calculate volume of acetone

  $\begin{array}{c}\text{density}=\frac{\text{mass}}{\text{volume}}\\ \text{volume}=\frac{\text{mass}}{\text{density}}\\ =\frac{\text{203}\text{.85 g}}{0.792\text{g}/\text{mL}}\\ =\text{257}\text{.38 mL}\end{array}$

So, the density of acetone is $\text{257}\text{.38 mL}$ .