Chapter 6, Problem 92A

Interpretation Introduction

Interpretation:

Mass of gasoline to be determine.

Concept Introduction :

Relation between mass, volume, and density is as shown:

  $\text{density}=\frac{\text{mass}}{\text{volume}}$

Answer to Problem 92A

Mass of gasoline is $\text{5,236 g}$ .

Explanation of Solution

The volume of gasoline is 7.7 L.

The density of gasoline is $0.68\text{g}/{\text{cm}}^{\text{3}}$

Relation between L and ${\text{cm}}^{\text{3}}$ is as follows:

  $1\text{ L}=1000{\text{ cm}}^{\text{3}}$

Convert volume into ${\text{cm}}^{\text{3}}$ as,

  $\begin{array}{c}\text{volume}=7.7\bcancel{\text{L}}\times \frac{1000{\text{ cm}}^{\text{3}}}{1\bcancel{\text{L}}}\\ ={\text{7,700 cm}}^{\text{3}}\end{array}$

Substitute value in the expression to calculate mass as,

  $\begin{array}{c}\text{density}=\frac{\text{mass}}{\text{volume}}\\ \text{mass}=\text{density}\times \text{volume}\\ =0.68\text{g}/{\text{cm}}^{\text{3}}\times {\text{7,700 cm}}^{\text{3}}\\ =\text{5,236 g}\end{array}$

Thus, mass of gasoline is $\text{5,236 g}$ .